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3 years ago

What is the place value of 1 in 209.631?

2 answers:

7 0

The thoasandthes place the 3 would be in the hundrethes place and the 6 would be in the tenths. Sorry for any spelling mistakes

svet-max [94.6K]3 years ago

6 0

The place of one is ONES

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PLEASE HELP ASAPPP!!!!

Mashutka [201]

Answer:

$\sqrt{(\frac{9c^{16} }{d^{4} })^{3} }=\frac{9c^{16} }{d^{4} } \sqrt{\frac{9c^{16}}{d^{4}} } \\\\= \frac{9c^{16} }{d^{4} }.\frac{3c^{8} }{d^{2} }=\frac{27c^{24} }{d^{6} }$

=> Amelia's answer is incorrect

Step-by-step explanation:

8 0

2 years ago

What is the range of the cluster in the scatter plot?

mestny [16]

I think that it is C

3 0

3 years ago

Read 2 more answers

Twice a number decreased by 16 is 64.

Artyom0805 [142]

You number is 40 40 x 2= 80- 16 =64 your welcome :)

8 0

2 years ago

Given B is between A and C, find the value of x if AB = 27, BC = 11x, and AC = 159

True [87]

Answer:

Step-by-step explanation:

Since, B is between A and C.

$\therefore AB + BC=AC \\ 27 + 11x = 159 \\ 11x = 159 - 27 \\ 11x = 132 \\ x = \frac{132}{11} \\ x = 12$

3 0

2 years ago

The rate of change of the number of squirrels S(t) that live on the Lehman College campus is directly proportional to 30 − S(t),

pishuonlain [190]

Answer:

S(3)=22

Step-by-step explanation:

The rate of change of the number of squirrels S(t) that live on the Lehman College campus is directly proportional to 30 − S(t).

$\dfrac{dS}{dt}=k(30-S(t))\\ \dfrac{dS}{dt}+kS(t)=30k\\$The integrating factor: e^{\int k dt}=e^{kt}\\$Multiply all through by the integrating factor\\ \dfrac{dS}{dt}e^{kt}+kS(t)e^{kt}=30ke^{kt}$

$(Se^{kt})'=30ke^{kt} dt\\$Integrate both sides\\ Se^{kt}=\dfrac{30ke^{kt}}{k}+C$ (C a constant of integration)\\Se^{kt}=30e^{kt}+C\\$Divide both sides by e^{kt}\\S(t)=30+Ce^{-kt}$

When t=0, S(t)=15

$15=30+Ce^{-k*0}\\C=15-30\\C=-15$

When t = 2, S(t)=20

$20=30-15e^{-2k}\\20-30=-15e^{-2k}\\-10=-15e^{-2k}\\e^{-2k}=\dfrac23\\$Take the natural log of both sides$\\-2k=\ln \dfrac23\\k=-\dfrac{\ln(2/3)}{2}$

Therefore:

$S(t)=30-15e^{\frac{\ln(2/3)}{2}t}\\$When t=3$\\S(t)=30-15e^{\frac{\ln(2/3)}{2} \times 3}\\S(3)=21.8 \approx 22$

8 0

2 years ago