The total distance traveled by the robot from t=0 to t=9 is 1422 units
Integration is a way in which smaller components are brought together in pieces to form a whole. Integration can be used in finding areas, volumes and so on.
Given that the position s(t) at any time t is given by the function:
s(t)=9t²−90t+4
The total distance traveled by the robot from t=0 to t=9 can be gotten by integrating the position function within the limits 0< t < 9
Therefore:
![Total\ distance = \int\limits^9_0 {s(t) \, dt \\\\Total\ distance = \int\limits^9_0 {(9t^2-90t+4) \, dt\\\\Total\ distance = [3t^3-45t+4t]_0^9\\\\Total\ distance=-1422\ units](https://tex.z-dn.net/?f=Total%5C%20distance%20%3D%20%5Cint%5Climits%5E9_0%20%7Bs%28t%29%20%5C%2C%20dt%20%5C%5C%5C%5CTotal%5C%20distance%20%3D%20%5Cint%5Climits%5E9_0%20%7B%289t%5E2-90t%2B4%29%20%5C%2C%20dt%5C%5C%5C%5CTotal%5C%20distance%20%3D%20%5B3t%5E3-45t%2B4t%5D_0%5E9%5C%5C%5C%5CTotal%5C%20distance%3D-1422%5C%20units)
The total distance is 1422 units
Find out more at: brainly.com/question/22008756
Answer:
9 meters
Step-by-step explanation:
V = 1/3 * pi * r^2 * h
339.12 = 1/3 * pi * 6^2 * h
h = 3 * (339.12)/(36 pi)
h = 9 meters
Answer:
No it is not.
Step-by-step explanation:
Reason.
For geometric: common ratio r should be equal
r = T2/T1 = T3/T2 but is not true here as -6/-14 is not equal to 2/-6
Here is the value of each decimal digit value
.4⇒ tenths place
.01⇒hundredths place
.006,thousandths place
So .416 is .416 rounded since there is nothing to round to
In other words, its already rounded to the nearest thousandths
Its kinda a trick question to make sure you know your place values
