Answer:
<h2>
y = ⁷/₂x - 52
</h2>
Step-by-step explanation:
The point-slope form of the equation is y - y₀ = m(x - x₀), where (x₀, y₀) is any point the line passes through and m is the slope:
m = ⁷/₂
(14, -3) ⇒ x₀ = 14, y₀ = -3
So, the point-slope form of the equation:
y + 3 = ⁷/₂(x - 14)
So::
y + 3 = ⁷/₂x - 49 {subtract 3 from both sides}
y = ⁷/₂x - 52 ← the slope-intercept form of the equation
Answer:
<em>5.33 secs</em>
Step-by-step explanation:
Given the equation of the height modeled by the equation/
h(t) = -3.2 + 12.5t + 24.8
The object strikes the ground when the height h(t) is zero
Substituting h(t) = 0 into the expression
h(t) = -3.2t² + 12.5t + 24.8
0 = -3.2t² + 12.5t + 24.8
-3.2t² + 12.5t + 24.8 = 0
Multiply through by minus sign
3.2t² - 12.5t - 24.8 = 0
From the expression a = 3.2, b = -12.5 and c = -24.8
t = -(-12.5)±√(-12.5)²-4(3.2)(-24.8)/2(3.2)
t = 12.5±√156.25+317.44)/6.4
t = 12.5±√473.69/6.42
t = 12.5±21.76/6.42
t = 12.5+21.76/6.42
t = 34.26/6.42
t = 5.33secs
<em>Hence the object strike the ground after 5.33 secs</em>
I didn't know which equation you were asking about, so I solved for both of them. I hope this helps!
Ignore the first guy who answered this question
Answer:
A 40 and 40
Step-by-step explanation: if two of the angles were cut by a transversal you would get A as an answer i think....
Answer:
B
Step-by-step explanation:
√256=16
√289=17
