<em><u>GIVEN</u></em><em><u> </u></em><em><u>EQUATION</u></em><em><u> </u></em><em>:</em><em>-</em>
<em>x</em><em> </em><em>+</em><em> </em><em>6</em><em> </em><em>y</em><em> </em><em>=</em><em> </em><em>9</em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em><u> </u></em><em><u> </u></em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>•</em><em>•</em><em>•</em><em> </em><em>(</em><em>i</em><em>)</em>
We have to find missing coordinate in ordered pair (2,?).
From ordered pair , we can observe that value of x is 2.
Putting value of x in equation (i).
2 + 6 y = 9
=> 6y = 9 -2
=> 6y = 7
=> y = 6/7
=> y = 0.8571428571
=> y = 0.86 (approx )
Now , ordered pair is ( 2, 0.86)
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Answer:
sorry i can not anderstand pls
-4 next to x value means the graph is moved 4 units to the right
+5 on the end of the function means the graph is moved up 5 units
Answer:
1
Step-by-step explanation:
Answer:
equation 1
y = -2x
equation 2
y = x-3
Solution to both
(1,-2)
Step-by-step explanation:
We need to get the equations of both lines
General form is;
y = mx + c
where m is slope and c is the y-intercept
Table 1
since we have a point 0,0; the y-intercept here is zero
Let us get the slope. We can do this by selecting any two points
m = (y2-y1)/(x2-x1)
m = (2-10)/(-1+5) = -8/4 = -2
So the equation of the first line is;
y = -2x
Table 2
we get the slope
m = (4+2)/(7-1) = 6/6 = 1
The partial equation is;
y = x + c
To get c, we select any two point and substitute
4 = 7 + c
c = 4-7
c = -3
So the equation is;
y = x-3
To get the solution to both systems, we equate the y
-2x = x - 3
-2x-x = -3
-3x = -3
x = -3/-3
x = 1
To get y, we substitute;
recall; y = -2x
y = -2(1)
y = -2
Solution to the system is;
(1,-2)