Question

A fish is swimming at 500 KM/hour and suddenly as shark appears behind, for 5 seconds the fish is swimming in the same direction but increases its speed to 2500 Km/H What is its average acceleration?

Answer 1

Answer:

$a =111.1\ m/s^2$

Step-by-step explanation:

The formula to calculate the average acceleration is:

$a =\frac{s_2-s_1}{t_2-t_1}$

Where s is the speed of the object and t is the time it takes the object to change its speed $s_1$ to the speed $s_2$

In this case we have that:

$t_2-t_1 = 5\ sec$

$s_1 = 500\ km/h = 500*\frac{1\ h}{3600\ s}*\frac{1000\ m}{1\ km}=138.89\ m/s$

$s_2= 2500\ km/h = 2500*\frac{1\ h}{3600\ s}*\frac{1000\ m}{1\ km}=694.44\ m/s$

$a =\frac{694.44-138.89}{5}\ m/s^2$

$a =111.1\ m/s^2$