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3 years ago

What is the smallest integer greater than square root of 148 ?

Mathematics

2 answers:

Yanka [14]3 years ago

7 0

The answer is 11 im pretty sure<span />

dimulka [17.4K]3 years ago

4 0

EXPLAINED ANSWER:

The square root of 148 is 12.1655250606.

Now with the options, you provided which are 13, 15, 14, 12, and 11, we can represent our known numbers on a number line.

----- | ----- | ----- | -*---- | ----- | ----- | ----- | -----
10 11 12 13 14 15 16

* = 12.1655250606

Now we can use the process of elimination to determine the smallest integer greater than the square root of 148.

15 is obviously too far to be the smallest integer greater than the square root of 148, so that is not the correct answer.

14 is pretty close to 12.1655250606, but we have three other options that are even closer so that cannot be the correct answer.

11 is also incredibly close to our square root, but there are two other options that are even closer. Therefore 11 will not be our answer.

Now that we have eliminated all other options but two of them, we have made it easy to determine which is correct.

12 is closer to 12.1655250606 than the number 13, so this would be the correct answer if the question was asking for the smallest integer of the square root of 148. But it is not.

The question asks for the smallest integer GREATER THAN the square root of 148. Therefore the correct answer to this question is 13.

QUICK ANSWER:

The smallest integer greater than the square root of 148 is 13.

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Hello,

First you have order all the number least to the greater. That gives 30, 75, 80, 85, 85, 95, 95, 100, 100, 110.

Afterwards you have to find the median. Why ?

I will explain you. It's because the median is robust. In fact, it can't be influenced by extreme values (example : 110) but the mean yes. So the mean won't be accurate.

"Then why don't you choose the mode ? " you will ask me. That's because the mode takes the number which appears most often in a set of numbers. It couldn't be accurate at all. It will be useless for this set of numbers.
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So the area of $R$ is given by

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(b) Find the intersections of the line $y=1$ with $y=e^{2x-x^2}$ .

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So the area of $S$ is given by

$\displaystyle\int_0^{1-\sqrt{1-\ln2}}\left(e^{2x-x^2}-1\right)\,\mathrm dx+\int_{1-\sqrt{1-\ln2}}^{1+\sqrt{1-\ln2}}(2-1)\,\mathrm dx+\int_{1+\sqrt{1-\ln2}}^2\left(e^{2x-x^2}-1\right)\,\mathrm dx$
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$\displaystyle\pi\int_0^2\left(e^{2x-x^2}-1\right)^2\,\mathrm dx$

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