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Studentka2010 [4]
2 years ago
11

a certain type of nuts are on sale at $.35 per pound. Tamara buys 0.2 pounds of nuts. how much will the nuts cost

Mathematics
2 answers:
Triss [41]2 years ago
4 0
Well you would divide .35 by 10 and get .035. then you do .035 times 2 and get .07 it costs 7 cents for .2 lbs. of nuts





agasfer [191]2 years ago
3 0

Answer:

$.35x2= $0.70

Step-by-step explanation:

0.35 x 2 gives you $.70

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Jorge has some dimes and quarters. He has 10 more dimes than quarters and the collection of coins is worth $2.40. How many dimes
PIT_PIT [208]

Answer:

14 dimes and 4 quarters

Step-by-step explanation:

x= number of dimes

y=number of quarters

x-10=y

0.10x+0.25y=2.40

substitute for y

0.10x+0.25(x-10)=2.40

0.35x-2.50=2.40

0.35x=4.90

x=14

y=4

5 0
2 years ago
The MagicSoft software company has a proposal to the city council of Alva, Florida, to relocate there. The proposal claims that
EleoNora [17]

Answer:

The correct estimate of the amount generated to the local economy is $3,333,333.\bar3

Step-by-step explanation:

The amount the expected to be generated for the local economy = $3.3 million

The amount of salaries that will generate $3.3 million = $1 million

The percentage of the amount of the salaries and the subsequent earnings expected to be spent on the local community = 70%

Therefore, we have;

For a first amount of 1 million into the economy, the next amount to into the economy is 70/100 × 1 million = 700,000, then we have 70/100 × 700,000 and so on, which is a geometric sequence, with first term, a = $1 million, the common ratio, r = 70/100 = 0.7, the number of terms = Infinity = ∞

The sum of a geometric sequence to infinity is given as follows;

\sum\limits_{k = 0}^{\infty }a \cdot r^k = S_{\infty} = \dfrac{a}{1 - r}

Substituting the known values gives;

\sum\limits_{k = 0}^{\infty }1,000,000 \times 0.7 ^k =  \dfrac{1,000,000}{1 - 0.7}= 3,333,333.\bar 3

Therefore, the correct estimate of the amount generated to the local economy by the $1 million salaries that will be paid = $3,333,333.\bar3.

5 0
2 years ago
11. How many different ways can the 16 numbered pool balls be placed in a line on the pool table?
nikklg [1K]

Answer:

The number of ways are 16! or 20,922,789,888,000.

Step-by-step explanation:

Consider the provided information.

We need to determine the number of different ways 16 numbered pool balls be placed in a line on the pool table.

For the first place we have 16 balls.

For the second place we have 15 balls left.

Similarly for the third place we have 14 balls as two balls are already arranged and so on.

Or we can say that this is the permutation of 16 things taking 16 at a time.

Thus the number of ways are: 16! or  ^{16}P_{16}

16!=16\times15\times14\times13......\times2\times1=20,922,789,888,000

Hence, the number of ways are 16! or 20,922,789,888,000.

7 0
3 years ago
The population of a city has increased by 27% since it was last measured. If the current population is 38,100, what was the prev
adoni [48]

Answer:

the previous population was 62,000.

Step-by-step explanation:

The current population of a city = 83,700

The population of a city has increased by 35% since it was last measured.

We have to calculate the previous population before increasing 35%.

Let the previous population be p

p +(35% × p) = 83,700

p + 0.35p = 83,700

1.35p = 83,700

p =  

p = 62,000

Therefore, the previous population was 62,000.

3 0
3 years ago
Read 2 more answers
the mgf of a random variable x is e^3(e^t-1). Find P[mean - standard deviation squared < X < 1/2( mean + standard deviatio
postnew [5]
The given MGF is that for a random variable following a Poisson distribution with parameter \lambda=3.

This means \mathbb E(X)=\mathbb V(X)=\lambda, and X has PMF

f_X(x)=\begin{cases}\dfrac{3^xe^{-3}}{x!}&\text{for }x\ge0\\0&\text{otherwise}\end{cases}

So, the desired probability is

\mathbb P\left(\lambda-\lambda^2

This is equivalent to

\displaystyle\sum_{x=0}^2\mathbb P(X=x)=\sum_{x=0}^2\frac{3^x}{x!e^3}=\frac{17}{2e^3}\approx0.4232
8 0
3 years ago
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