1) Vertex: (0,2) AOS x=0 table : x = -1, 0, 1 x^2+2 = 3, 2, 3 (x,y) = (-1,3), (0,2), (1,3) 2) vertex: (-5, -1) AOS x= -5 table : x = -7, -6, -5, -4, -3 x^2+10x+24 = 3, 0, -1, 0, 3 (x,y) = (-7,3), (-6,0), (-5,-1), (4,0), (-3,3) 3) vertex: (4, -1) AOS x=4 table : x = 2, 3, 4, 5, 6 y = 3, 0, -1, 0, 3 (x,y) = (2, 3), (3, 0), (4, -1), (5, 0), (6, 3) if the picture didn’t attach along with this then just use the points i gave (x,y) to plot a graph. always remember that whenever your equation has x^2 in it, it is a parabola. and do not forget to write down “y=“. my teacher takes off a lot of points if i don’t. have a great day!
If you work by process of elimination all you have to do is take 27 away from the bigger degree of the two and see if it is 2x as much as the smaller degree.
Nikolai Lobachevsky (A russian mathematician born in 1792) and Bernhard Riemann (A german mathematician born in 1826) are the mathematicians that helped to discover alternatives to euclidean geometry in the nineteenth century.
We can use the Central Angle Theorum, which states that if the vertex of the angle is the center of the circle, then the arc is the same measurement as the angle.
In this case, m<COB is 80 degrees, and the vertex is the center of the circle, which means that measure of arc CB is also 80 degrees
