1) Vertex: (0,2) AOS x=0 table : x = -1, 0, 1 x^2+2 = 3, 2, 3 (x,y) = (-1,3), (0,2), (1,3) 2) vertex: (-5, -1) AOS x= -5 table : x = -7, -6, -5, -4, -3 x^2+10x+24 = 3, 0, -1, 0, 3 (x,y) = (-7,3), (-6,0), (-5,-1), (4,0), (-3,3) 3) vertex: (4, -1) AOS x=4 table : x = 2, 3, 4, 5, 6 y = 3, 0, -1, 0, 3 (x,y) = (2, 3), (3, 0), (4, -1), (5, 0), (6, 3) if the picture didn’t attach along with this then just use the points i gave (x,y) to plot a graph. always remember that whenever your equation has x^2 in it, it is a parabola. and do not forget to write down “y=“. my teacher takes off a lot of points if i don’t. have a great day!
There's only one face, and only one vertex that leads to a single base. There are no edges because the base perimeter is not considered to be an edge because it's a vertex.
The time needed at 2 meters per second for both rounds would be 100/2 s or 50 seconds. For the first lane he already used 50/1.5 -> 33.33 seconds, so he would need to cover the other 50 meters in exactly 16.67. 50m divided by the 16.67 seconds he has left means he has to swim at a speed of 3 meters per second.
