40 * 39 * 38 * 37 * 36 = 78,960,960
Therefore, the answer is A, 78,960,960.
Answer:
Answer is 0.696
Step-by-step explanation:
The sum number of sets possible for no two students to have the same birthday in a class of 30 is:
=30 * (30-1)/2
= 435.
Now, there are 365 days in a year. Therefore, the probability of students having a birthday on a different date would be 364/365. Now there are a number of combination, to be exact 870 combinations.
So, the probability that no two students having the same birthday is:
(364/365)^435 = 0.303.
Now, the probability that two students would have their birthdays on the same equal date would be:
1-0.303 = 0.696 or 70%
Answer:
9.28
Step-by-step explanation:
hope this help!!!
Answer: a) AB = ![\left[\begin{array}{ccc}-14&26\\-11&22\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-14%2626%5C%5C-11%2622%5Cend%7Barray%7D%5Cright%5D)
; b) ![\left[\begin{array}{ccc}5&-5\\13&9\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%26-5%5C%5C13%269%5Cend%7Barray%7D%5Cright%5D)
; c) No, they are different; d) No, they are never the same;
Step-by-step explanation:
a) A = ![\left[\begin{array}{ccc}-2&4\\1&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%264%5C%5C1%263%5Cend%7Barray%7D%5Cright%5D)
, B = ![\left[\begin{array}{ccc}-2&1\\-3&7\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%261%5C%5C-3%267%5Cend%7Barray%7D%5Cright%5D)
. This multiplication is possible, because matrix A has 2 columns and matrix B has 2 rows. When those value are equal, the multiplication is possible.
AB = . =
b) BA = . =
c) As, we can see, parts a and b are differents.
d) With matrices, multiplication is not commutative, which means AB≠BA
