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Stolb23 [73]
3 years ago
11

Tell what number must be added to complete the square x^2+16x__

Mathematics
1 answer:
Talja [164]3 years ago
8 0
2 will work.
if you use two the answer is.
(x-4)(x+4)
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What is the scale factor from figure A to figure B?
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Answer:

hi its simple.

Step-by-step explanation:

9;3

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3;1

3 0
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Guys help please I am struggling
alina1380 [7]

9514 1404 393

Answer:

  14.1 years

Step-by-step explanation:

Use the compound interest formula and solve for t. Logarithms are involved.

  A = P(1 +r/n)^(nt)

amount when P is invested for t years at annual rate r compounded n times per year.

Using the given values, we have ...

  13060 = 8800(1 +0.028/365)^(365t)

  13060/8800 = (1 +0.028/365)^(365t) . . . . divide by P=8800

Now we take logarithms to make this a linear equation.

  log(13060/8800) = (365t)log(1 +0.028/365)

Dividing by the coefficient of t gives us ...

  t = log(13060/8800)/(365·log(1 +0.028/365)) ≈ 0.171461/0.0121598

  t ≈ 14.1

It would take about 14.1 years for the value to reach $13,060.

8 0
3 years ago
Which pair of expressions is equivalent?
riadik2000 [5.3K]
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4 0
3 years ago
What are the solutions of the equation?<br>15 - 8x^2 – 14x​
ipn [44]
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6 0
3 years ago
the mass of the sun is 2 x 10^30kg and the mass of earth is 6 * 10^24 kg. Approximately how many times greater is the mass of th
german

Answer:

The mass of sun is 333333.33 times greater than the mass of earth

Step-by-step explanation:

Given as :

The mass of the sun = 2\times 10^{30} kg

The mass of earth =  6\times 10^{24} kg.

Let The mass of sun is x times greater than the mass of earth

i.e The mass of sun = x × The mass of earth

or,  2\times 10^{30} kg =  6\times 10^{24} kg × The mass of earth

Or, x = \dfrac{2\times 10^{30}}{6\times 10^{24}}

Or, x = \dfrac{2\times 10^{6}}{6}

∴ x = 333333.33

So,  The mass of sun = 333333.33 × The mass of earth

Hence, The mass of sun is 333333.33 times greater than the mass of earth Answer

6 0
3 years ago
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