$495.28 I think I'm not sure if I'm right.
Answer:
Step-by-step explanation:
Given that X - the distribution of heights of male pilots is approximately normal, with a mean of 72.6 inches and a standard deviation of 2.7 inches.
Height of male pilot = 74.2 inches
We have to find the percentile
X = 74.2
Corresponding Z score = 74.2-72.6 = 1.6
P(X<174.2) = P(Z<1.6) = 0.5-0.4452=0.0548=5.48%
i.e. only 5% are below him in height.
Thus the malepilot is in 5th percentile.
11x+9
Step by step:
Remove the parenthesis
3x+7+8x+2
Collect like terms
11x+7+2
Add 7+2
11x+9
A. 6, 7, 8, 9
B. 2, 5, 8, 11
C. 5, 8, 13, 20
D. 3, 12, 27, 48