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dimulka [17.4K]
3 years ago
12

These temperatures were recorded in International Falls, Minnesota, on four consecutive days: day 1: -10°F day 2: -13°F day 3: -

8°F day 4: -11°F On which day was the temperature farthest from 0°F ?
Mathematics
1 answer:
Gwar [14]3 years ago
5 0

day 2 is your answer

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Bill claims that he found the actual December temperature by adding either –5 + 3 or 3 + –5.
MaRussiya [10]

Answer:

This would be the commutative property because in either order the sum will always be the same.

You were asking about the property type, right?

8 0
3 years ago
What is 52 divide by 69
vampirchik [111]

Answer:

Its 52/69... did u mean 69 divide by 52? If so the answer is 69/52.

Step-by-step explanation:

Hopefully u wrote the answer correctly, as always plz mark as brainliest. Hope this helps!

Oh wait!

The decimal form is: 0.753621 i think

5 0
3 years ago
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Which expression is not equivalent to 8+(n-4)
MrRa [10]
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4 0
3 years ago
What is the fraction for 45 divided by 20 please show work
lianna [129]

Answer:

9/4

Step-by-step explanation:

The divide symbol is also the line that separates the numerator and the denominator, so 45÷20 can also be written as 45/20.

We can see that both 45 and 20 are divisible by 5, so we can simplify the fraction down to 9x5/4x5, and then we cancel out the 5s and are left with 9/4

4 0
3 years ago
Sample spaces For each of the following, list the sample space and tell whether you think the events are equally likely:
Schach [20]

Answer and explanation:

To find : List the sample space and tell whether you think the events are equally likely ?

Solution :

a) Toss 2 coins; record the order of heads and tails.

Let H is getting head and t is getting tail.

When two coins are tossed the sample space is {HH,HT,TH,TT}.

Total number of outcome = 4

As the outcome HT is different from TH. Each outcome is unique.

Events are equally likely since their probabilities \frac{1}{4} are same.

b) A family has 3 children; record the number of boys.

Let B denote boy and G denote girl.

If there are 3 children then the sample space is

{GGG,GGB,GBG,BGG,BBG,GBB,BGB,BBB}

The possible number of boys are 0,1,2 and 3.

Number of boys      Favorable outcome    Probability

           0                      GGG                        \frac{1}{8}

           1                    GGB,GBG,BGG          \frac{3}{8}

           2                   GBB,BGB,BBG           \frac{3}{8}

           3                       BBB                         \frac{1}{8}

Since the probabilities are not equal the events are not equally likely.

c)  Flip a coin until you get a head or 3 consecutive tails; record each flip.

Getting a head in a trial is dependent on the previous toss.

Similarly getting 3 consecutive tails also dependent on previous toss.

Hence, the probabilities cannot be equal and events cannot be equally likely.

d) Roll two dice; record the larger number

The sample space of rolling two dice is

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

Now we form a table that the number of time each number occurs as maximum number then we find probability,

Highest number        Number of times         Probability

           1                                   1                     \frac{1}{36}

           2                                  3                    \frac{3}{36}

           3                                  5                    \frac{5}{36}

           4                                  7                    \frac{7}{36}

           5                                  9                    \frac{9}{36}

           6                                  11                    \frac{11}{36}

Since the probabilities are not the same the events are not equally likely.

4 0
3 years ago
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