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3 years ago

Explain a real world situation where you would. need to multiply with negative or rational numbers

1 answer:

7 0

Let us say you must pay someone ten dollars a month. This is the same as being paid negative ten dollars a month. Ten months ago (in negative ten months) you were 100 dollars richer *. (-10)x(-10)=100

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Thickness measurements of ancient prehistoric Native American pot shards discovered in a Hopi village are approximately normally

storchak [24]

Answer:

a) 0.1587

b) 0.0475

c) 0.7938

Step-by-step explanation:

Let's start defining our random variable.

X : ''Thickness (in mm) of ancient prehistoric Native American pot shards discovered in a Hopi village''

X is modeled as a normal random variable.

X ~ N(μ,σ)

Where μ is the mean and σ is the standard deviation.

To calculate all the probabilities, we are going to normalize the random variable X.

We are going to call to the standard normal distribution ''Z''.

[(X - μ) / σ] ≅ Z

We normalize by subtracting the mean to X and then dividing by standard deviation.

We can find the values of probabilities for Z in a standard normal distribution table.

We are going to call Φ(A) to the normal standard cumulative distribution evaluated in a value ''A''

$P(X$

$P(Z$ Φ(-1) = 0.1587

$P(X>7)=P(\frac{X-4.5}{1.5}>\frac{7-4.5}{1.5})$

$P(Z>1.666)=1-P(Z\leq 1.666)=$

1 - Φ(1.666) = 1 - 0.9525 = 0.0475

$P(3$

$P(-1$ Φ(1.666) - Φ(-1) = 0.9525 - 0.1587 = 0.7938

8 0

3 years ago

What value of x is in the solution set of 4x – 12 ≤ 16 + 8x?Which is a correct first step in solving the inequality –4(2x – 1) &

Anna71 [15]

Value of x is -1
The correct first step to solving the inequality is distributing the -4 into the para thesis

8 0

3 years ago

Read 2 more answers

We have two fair three-sided dice, indexed by i = 1, 2. Each die has sides labeled 1, 2, and 3. We roll the two dice independent

Bogdan [553]

Answer:

(a) P(X = 0) = 1/3

(b) P(X = 1) = 2/9

(d) P(X = 3) = 0

(a) P(Y = 0) = 0

(b) P(Y = 1) = 1/3

Step-by-step explanation:

Given:

- Two 3-sided fair die.

- Random Variable X_1 denotes the number you get for rolling 1st die.

- Random Variable X_2 denotes the number you get for rolling 2nd die.

- Random Variable X = X_2 - X_1.

Solution:

- First we will develop a probability distribution of X such that it is defined by the difference of second and first roll of die.

- Possible outcomes of X : { - 2 , -1 , 0 ,1 , 2 }

- The corresponding probabilities for each outcome are:

( X = -2 ): { X_2 = 1 , X_1 = 3 }

P ( X = -2 ): P ( X_2 = 1 ) * P ( X_1 = 3 )

: ( 1 / 3 ) * ( 1 / 3 )

: ( 1 / 9 )

( X = -1 ): { X_2 = 1 , X_1 = 2 } + { X_2 = 2 , X_1 = 3 }

P ( X = -1 ): P ( X_2 = 1 ) * P ( X_1 = 3 ) + P ( X_2 = 2 ) * P ( X_1 = 3)

: ( 1 / 3 ) * ( 1 / 3 ) + ( 1 / 3 ) * ( 1 / 3 )

: ( 2 / 9 )

( X = 0 ): { X_2 = 1 , X_1 = 1 } + { X_2 = 2 , X_1 = 2 } + { X_2 = 3 , X_1 = 3 }

P ( X = -1 ):P ( X_2 = 1 )*P ( X_1 = 1 )+P( X_2 = 2 )*P ( X_1 = 2)+P( X_2 = 3 )*P ( X_1 = 3)

: ( 1 / 3 ) * ( 1 / 3 ) + ( 1 / 3 ) * ( 1 / 3 ) + ( 1 / 3 ) * ( 1 / 3 )

: ( 3 / 9 ) = ( 1 / 3 )

( X = 1 ): { X_2 = 2 , X_1 = 1 } + { X_2 = 3 , X_1 = 2 }

P ( X = 1 ): P ( X_2 = 2 ) * P ( X_1 = 1 ) + P ( X_2 = 3 ) * P ( X_1 = 2)

: ( 1 / 3 ) * ( 1 / 3 ) + ( 1 / 3 ) * ( 1 / 3 )

: ( 2 / 9 )

( X = 2 ): { X_2 = 1 , X_1 = 3 }

P ( X = 2 ): P ( X_2 = 3 ) * P ( X_1 = 1 )

: ( 1 / 3 ) * ( 1 / 3 )

: ( 1 / 9 )

- The distribution Y = X_2,

P(Y=0) = 0

P(Y=1) = 1/3

P(Y=2) = 1/ 3

- The probability for each number of 3 sided die is same = 1 / 3.

7 0

3 years ago

-1 1/2 + (-1 1/2 <br> i need help

kirza4 [7]

-3
When there are two negative be added your answer will always be negative. In this case add the ones(2) and then add the 1/2s(1) and then add the two. For this you’ll get 3 but just add the negative sign.

6 0

3 years ago

Adult tickets to the fall play cost $6 and student tickets cost $3. The drama class sold 25 more student tickets than adult tick

svlad2 [7]

9514 1404 393

Answer:

90 student tickets
65 adult tickets

Step-by-step explanation:

For many "mixture" problems, it is convenient to use a variable for the quantity of the highest contributor. Here, we can use 'a' to represent the number of adult tickets, because adult tickets cost the most. Then the number of student tickets is (a+25), and the total revenue is ...

6a +3(a+25) = 660

9a +75 = 660

9a = 585

a = 65

(a+25) = 90

The drama class sold 90 student tickets and 65 adult tickets.

6 0

3 years ago

Explain a real world situation where you would. need to multiply with negative or rational numbers​

Explain a real world situation where you would. need to multiply with negative or rational numbers