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Vikki [24]
3 years ago
11

De sua jarra de suco, Claudete bebeu inicialmente 240 ml. Depois, bebeu 1/4 do que restava e, depois de algum tempo, ela bebeu o

restante que representava 1/3 do volume inicial. A jarra continha inicialmente uma quantidade de suco, em ml, igual a?
Mathematics
1 answer:
docker41 [41]3 years ago
4 0
É uma questão relativamente simples, o problema é cair em uma pegadinha do enunciado.

Se colocarmos que o jarro inicialmente tenha X ml, após Claudete beber 240 ml temos que X-240=Y. Então Claudete bebe 1/4 da jarra, por isso temos 3*Y/4=Z (Se ela bebeu 1/4, reataram 3/4). Depois, ela bebe 1/3 do volume inicial e o suco acaba, logo montamos a equação X/3=Z.

Agora temos um sistema com estas 3 equações:
--> X-240=Y
-->3Y/4=Z
-->Z=X/3

Juntando as 2 ultimas vc terá: X/3=3Y/4. E como Y=X-240.

X/3=3*(X-240)/4

Se resolver isto terá que X=432. logo a resposta é 'E'
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