Initial velocity of the plane is Vo = 0.
acceleration a = 1.3 m/s2
total distance = 2.5 km = 2500m
time taken to reach 2.5 km with 1.3m/s^2 acceleration = t
S = Vo t + 0.5 a t^2
2500 = 0 + (0.5*1.3* t^2)
t^2 = 3846.15
t = 62 s
the maximum velocity plan can reach within 62 s is Vt
Vt = Vo + a t
Vt = 0 + (1.3*62)
Vt = 80.6 m/s
Since 80.6 m/s is greater than 75 m/s, plane can use this runway to takeoff with required speed.
I think its 9000(1.045)^5. Hope this helps. That equals $11,215.60, or rounded to the nearest dollar, $11,215.
Answer:
d. interquartile range
Step-by-step explanation:
the iqr measures the first, second, and third quartile, and the median.
Answer: 
Step-by-step explanation:
Given: The rent of waterslide per day = $500
Let x be the a charge per hour of use.
The number of hours bounce house was used = 5 hours
Since, the total charge was $800.
Therefore, the equation can be used to find the charge x, in dollars, per hour of use is given by :-
Fixed charge+5 times x=Total charge
Answer:
415,801
Step-by-step explanation:
415,801 + 96,473 = 512,274
