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Finger [1]
3 years ago
8

Solve 2x - 1 < 7 and 5x + 3 < 3. {x | x < 0} {x | x < 4} {x | 0 < x < 4}

Mathematics
2 answers:
nataly862011 [7]3 years ago
7 0
2x -1 <7 ; then, 2x < 8; then x < 4;
5x + 3 < 3; then, 5x < 0; then x < 0;
Finally, {x / x < 0};
saul85 [17]3 years ago
3 0

Answer:

Solution for givrn system of inequalities: \{x ~| ~x < 0\}

Step-by-step explanation:

We are given a system of two inequalities:

2x-1 < 7\\5x+3 < 3

Solving the inequalities individually:

2x-1 < 7\\2x

The intersection of the two solution will give us the solution to the system of inequalities:

x \in (-\infty, 4) \cap (-\infty, 0)\\ x \in (-\infty, 0) \\\{x ~| ~x < 0\}

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