Plug the -4 into equation
f(-4) = 5(-4) -3
multiply 5•-4= -20
then subtract -20-3
when you have two negatives you add
= -23
Answer:
24
Step-by-step explanation:
The question is saying, how many three digit numbers can be made from the digits 3, 4, 6, and 7 but there can't be two of the same digit in them. For example 346 fits the requirements, but 776 doesn't, because it has two 7s.
Okay, on to the problem:
We can do one digit at a time.
First digit:
There are 4 digits that we can choose from. (3, 4, 6, and 7)
Second digit:
No matter which digit we chose for the first digit, there is only going to be 3 of them left, because we already chose one, and you can't repeat that same digit. So there are 3 options.
Third digit:
Using the same logic, there are only 2 options left.
We have 4 choices for the first digit, 3 choices for the second, and 2 for the third.
Hence, this is 4 * 3 * 2 = 24 three-digit numbers that can be made.
Answer:
5/6 = 20/24
5/8 = 15/24
Step-by-step explanation:
These are the answers because:
1) First, the least common denominator is 24 because 8 x 3 is 24 and 6 x 4 is 24
2) Next, multiply the numerators with the same number you multiplied with the denominator
5 x 3 = 15
5 x 4 = 20
3) Therefore, the answers are:
5/6 = 20/24
5/8 = 15/24
Hope this helps!
Answer:
The result will always be the same
Step-by-step explanation:
Answer:
Es in simplo deviso con lado
