Completed question:
In the game of tic-tac-toe, if all moves are performed randomly the probability that the game will end in a draw is 0.127. Suppose six random games of tic-tac-toe are played. What is the probability that at least one of them will end in a draw?
Answer:
0.557
Step-by-step explanation:
For each game, the probability of not end in a draw is 1 - 0.127 = 0.873. Thus, because each game is independent of each other, the probability of all of them not end in a draw is the multiplication of the probability of each one:
0.873x0.873x0.873x...x0.873 = 0.873⁶ = 0.443
Thus, the probability that at least one of them end in a draw is the total probability (1) less the probability that none of them en in a draw:
1 - 0.443
0.557
Answer:
0.336 or 33.6%
Step-by-step explanation:
It follows from the question that the probability of a complaint is 35% = 35/100 = 0.35. Let's call this probability, p.
The probability of no complaint is mutually exclusive of p since both are complements. Let's call this q. Then
q = 1 - p = 1 - 0.35 = 0.65
The distribution is a binomial distribution.
Events of each call are independent.
The probability of 2 calls with complaint out of 5 is
Answer:
Well, 10
Step-by-step explanation:
Because I am SMART
