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3 years ago

How do you solve this equation in algebra-7x=-7x

Mathematics

1 answer:

MA_775_DIABLO [31]3 years ago

7 0

Answer:

if both sides are equal x's, then they are all real numbers. so 16x=16x, means it's all real numbers. 16x=16 is equal to x=1, dont mix this up.

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What is expanded form for 1111.111

valentina_108 [34]

1111.111 in expanded form is 1000 + 100 + 10 + 1 + 0.1 + 0.01 + 0.001

5 0

3 years ago

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Fully condense the expression. Assume that all variables represent positive numbers. (log x -2 log y+ 3 log z) (10 points)

AfilCa [17]

Answer: The required condensed expression is $\log\dfrac{xz^3}{y^2}.$

Step-by-step explanation: We are given to fully condense the following logarithmic expression assuming that all variables represent positive numbers :

$E=\log x-2\log y+3\log z~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

We will be using the following properties of logarithms :

$(i)~\log a^b=b\log a,\\\\(ii)~\log a+\log b=\log(ab),\\\\(iii)~\log a-\log b=\log\dfrac{a}{b}.$

Therefore, from expression (i), we get

$E\\\\=\log x-2\log y+3\log z\\\\=\log x-\log y^2+\log z^3\\\\=\log(xz^3)-\log y^2\\\\=\log\dfrac{xz^3}{y^2}.$

Thus, the required condensed expression is $\log\dfrac{xz^3}{y^2}.$

5 0

3 years ago

She buy candy for $1.80 and other one but she only have $20so how much she have left?

Verdich [7]

$16.40 because she bought 2 candies so you will add 1.80 +1.80 or could of times 1.80x2 then subtract $20 for what you get adding or multiplying then that's how you get what she has left.

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3 years ago

John is creating a Thanksgiving display at the store where he works, using only canned pumpkin and canned green beans. He needs

nadya68 [22]

Well 3x(pumpkin) + 1x ( beans ) =4x so 4x=76
divide 76 by four to get x=19
so 19 cans of beans

7 0

3 years ago

Help help help help help

wariber [46]

Answer:

Step-by-step explanation:

1) (-6 , 2) ; (3 , -5)

Slope = $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$= \frac{-5-2}{3-[-6]}\\\\= \frac{-5-2}{3+6}\\\\= \frac{-7}{9}\\$

m = -7/9 ; (-6 , 2)

y - y₁ = m(x -x₁)

y - 2 = (-7/9)(x - [-6])

$y - 2 = \frac{-7}{9}(x + 6)\\\\y -2 = \frac{-7}{9}x + \frac{-7}{9}*6\\\\y - 2 = \frac{-7}{9}x - \frac{7*2}{3}\\\\ y = \frac{-7}{9}x - \frac{14}{3} + 2\\\\y = \frac{-7}{9}x -\frac{14}{3} + \frac{2*3}{1*3}\\\\y = \frac{-7}{9}x - \frac{14}{3} + \frac{6}{3}\\\\y = \frac{-7}{9}x - \frac{8}{3}$

2) (3 , -4) ; m= 3

$y - y_{1} = m(x - x_{1}$ )

y - [-4] = 3(x - 3)

y + 4 = 3x - 3*3

y + 4 = 3x - 9

y = 3x - 9 - 4

Ans: y = 3x - 13

3) m = 2 ; y-intercept (b) = 3/2

y = mx + b

Ans: y = 2x + (3/2)

4) (-1, 3 ) ; (2 , 0)

Slope = $\frac{0 - 3}{2-[-1]}$

$= \frac{-3}{2+1}\\\\= \frac{-3}{3}\\\\= 1$

m = 1; ( -1 , 3)

y - 3 = 1(x -[-1])

y - 3 = 1(x + 1)

y - 3 = x + 1

y = x + 1 + 3

Ans: y = x + 4

5)(2, 1) ;m = -3

y - 1 = (-3)(x - 2)

y - 1 = -3x + 6

y = -3x + 6 +1

Ans: y = -3x + 7

5 0

3 years ago

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