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Nookie1986 [14]
4 years ago
10

Which of the following is the abbreviation for a nucleotide containing the nitrogenous base cytosine, a hydrogen at the 2’ carbo

n of its pentose sugar, and a di-phosphate group attached to the 5’ carbon of its pentose sugar?

Chemistry
1 answer:
zvonat [6]4 years ago
4 0

Answer:

dCDP

Explanation:

The nucleotide has hydrogen at it second carbon which means that it has deoxy pentose sugar which is written in small d as prefix.

The nitrogenous base is cytosine and it contains 2 phosphate groups which are attached to the 5 carbon of the pentose sugar means it is cytosine diphosphate.

<u>So, the abbrevation of the molecule is : dCDP</u>

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A gas is heated from 263.0 K to 298.0 K and the volume is increased from 24.0 liters to 35.0 liters by moving a large piston wit
Triss [41]

Answer:

The final pressure is approximately 0.78 atm

Explanation:

The original temperature of the gas, T₁ = 263.0 K

The final temperature of the gas, T₂ = 298.0 K

The original volume of the gas, V₁ = 24.0 liters

The final volume of the gas, V₂ = 35.0 liters

The original pressure of the gas, P₁ = 1.00 atm

Let P₂ represent the final pressure, we get;

\dfrac{P_1 \cdot V_1}{T_1} = \dfrac{P_2 \cdot V_2}{T_2}

P_2 = \dfrac{P_1 \cdot V_1 \cdot T_2}{T_1 \cdot V_2}

P_2 = \dfrac{1 \times 24.0 \times 298}{263.0 \times  35.0} = 0.776969038566

∴ The final pressure P₂ ≈ 0.78 atm.

4 0
3 years ago
A sample of 40.0 mL of hydrogen is collected by water displacement at a temperature of 20 degrees Celcius. The barometer reads 7
Roman55 [17]

Answer : The volume of the hydrogen at STP is, 36.8 mL

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 751 torr

P_2 = final pressure of gas at STP = 760 torr

V_1 = initial volume of gas = 40.0 mL

V_2 = final volume of gas at STP = ?

T_1 = initial temperature of gas = 20^oC=273+20=293K

T_2 = final temperature of gas at STP = 0^oC=273+0=273K

Now put all the given values in the above equation, we get:

\frac{751torr\times 40.0mL}{293K}=\frac{760torr\times V_2}{273K}

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6 0
3 years ago
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3 years ago
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Inessa05 [86]
Right Side:
H- 1
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Left Side:
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The equation is unbalanced.
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3 years ago
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Amanda [17]

Answer:

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