The term that best described a 10 gram of KClO3 per 100 grams of water solution at 30 degree Celcius is Saturated. The solubility chart is needed for this work. If the solubility chart is drawn for KClO3, it will be observed that the proportion of KClO3 that is needed to dissolve in 100ml of water to make the solution saturated is 10 grams at 30 degree Celcius.
Answer:
The direction of the field is taken to be the direction of the force it would exert on a positive test charge. The electric field is radially outward from a positive charge and radially in toward a negative point charge.
Explanation:
Answer:
D. 77.0%
Explanation:
% yield = actual yield/theoretical yield x 100%
% yield = 1.57 g / 2.04 g x 100%
% yield = 76.96 (round up)
<span>Answer:
molality = (moles of solute) / (kilogram of solvent)
moles of solute = (75.2 g AgClO4) / (mole mass AgClO4)
moles of solute = (75.2 g AgClO4) / (207.3206 g/mol)
moles of solute = 0.3627232 mol
molality = (0.3627232 mol) / (0.0752 Kg)
molality = 4.8234468 m or 4.82 m rounded to three significant figures </span>
C. Sodium chloride
hope it helps u hehe :)
