<u>Answer:</u> The correct statement is low temperature only, because entropy decreases during freezing.
<u>Explanation:</u>
The relationship between Gibb's free energy, enthalpy, entropy and temperature is given by the equation:
Where,
= change in Gibb's free energy
= change in enthalpy
T = temperature
= change in entropy
It is given that freezing of methane is taking place, which means that entropy is decreasing and 
is becoming negative. It is also given that the reaction is an exothermic reaction, this means that the is also negative.
For a reaction to be spontaneous, must be negative.
![-ve=-ve-[T(-ve)]\\\\-ve=-ve+T](https://tex.z-dn.net/?f=-ve%3D-ve-%5BT%28-ve%29%5D%5C%5C%5C%5C-ve%3D-ve%2BT)
From above equations, it is visible that will be negative only when the temperature will be low.
Hence, the correct statement is low temperature only, because entropy decreases during freezing.
Answer:
4
Explanation:
in order for the bobber to float,it must be less dense, and for the line to sink, it must be more dense.
The correct answer is 3.4 moles of sulfuric acid (H₂SO₄) are needed to react completely with 6.8 moles of lithium hydroxide.
2LiOH + H₂SO₄ → Li₂SO₄ + 2H₂O
The given chemical equation is balanced.
By using stoichiometry, one can witness the following:
2 moles of LiOH requires 1 mole of H₂SO₄
So, 6.8 moles of LiOH requires (1/2) × 6.8 = 3.4 moles of H₂SO₄
