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vampirchik [111]
3 years ago
15

What is the missing term in the factorization of 2x2+5x+3

Mathematics
1 answer:
levacccp [35]3 years ago
5 0

the answer is x=35 because 2 times 2 is 4 plus 3 = 7 and 7x5= 35 so x=35

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Write the equation of a line in point Slope form that passes through the points (-8,-3) and (2,2)
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Answer:

The midpoint of the points (2,8) and (0,4) is given by:

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We must must transform the standard form equation −3x+6y=5 into a slope-intercept form equation (y=mx+b) to find its slope.

−3x+6y=5 (Subtract 3x on both sides.)

6y=3x+5 (Divide both sides by 6.)

y=

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The slope of our first line is equal to

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Since the equation of line passing through the midpoint (1,6), therefore, substitute the given point in the equation y=−2x+b:

6=(−2×1)+b

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y=−2x+8

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Step-by-step explanation:

make me as brain liest

4 0
3 years ago
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hram777 [196]

Answer:

If Anne’s age is represented by the variable a then express Jenny’s age in terms of a if Jenny is three years less than half of Anne’s age

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\begin{array}{|cc|ll} \cline{1-2} x&y\\ \cline{1-2} 0&4\\ 1&10\\ 2&16\\ 3&22\\ 4&28\\ \cline{1-2} \end{array} \begin{array}{llll} \\ \leftarrow \textit{let's use this point}\\\\ \leftarrow \textit{and this point} \end{array}

(\stackrel{x_1}{1}~,~\stackrel{y_1}{10})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{22}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{22}-\stackrel{y1}{10}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{1}}}\implies \cfrac{12}{2}\implies 6 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{10}=\stackrel{m}{6}(x-\stackrel{x_1}{1}) \\\\\\ y-10=6x-6\implies y=6x+4

7 0
1 year ago
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