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3 years ago

What is the missing term in the factorization of 2x2+5x+3

Mathematics

1 answer:

levacccp [35]3 years ago

5 0

the answer is x=35 because 2 times 2 is 4 plus 3 = 7 and 7x5= 35 so x=35

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Find a three digit number. The tens digit is 3 time the hundreds digit. The sum of the digits is 15. If you reverse the digits,

tresset_1 [31]

Answer:

number = 267

Step-by-step explanation:

i am a 3 digit number divisible by 3.

100a + 10b + c

my tens digit is 3 times as great as my hundreds digit

b = 3a, from this we know a = 1, 2, 3, then b = 3, 6, 9

and the sum of my digits is 15.

a + b + c = 15

if you reverse my digits i am divisible by 6 and 3

100c + 10b + a

this is a logic problem, an equation won't help us here

From the given information b = 3a, and the sum of the 3 digits = 15, we have:

1 3 ___; three single digits can't add up to 15

2 6 _7_; this has to be the number

3 9 _3_; reverse number is not different

Check for division by 3 and 6

267/3 = 89

762/6 = 127

267 is the number

3 0

3 years ago

I NEED HELP PLEASE HELP ME

Aloiza [94]

Answer:
294.14cm^2

Explanation:

First find the area of the whole piece of paper:
32*14=448

Then find the area of the two semicircles, semicircle + semicircle = 1 circle:

Area of a circle= (radius squared)(pi):
(7^2)(3.14) = 153.86

Subtract the area of the two semicircles from the whole paper area:
448-153.86 = 294.14

I hope this isn’t too confusing :)

5 0

3 years ago

Jasmine sells bracelets at a local jewelry store in South Dekalb Mall. She has 1,190 purple beads and 2,125 pink beads. Each bra

jeka57 [31]

Answer:

Step-by-step explanation:

1190 + 2125 = 3315 (number of beads)

3315/85 = 36 (number of bracelets jasmine can make)

8 0

3 years ago

Help me pls !!! answer all pls

polet [3.4K]

1. We assume, that the number 128 is 100% - because it's the output value of the task.
2. We assume, that x is the value we are looking for. 
3. If 128 is 100%, so we can write it down as 128=100%. 
4. We know, that x is 51% of the output value, so we can write it down as x=51%. 
5. Now we have two simple equations:
1) 128=100%
2) x=51%
where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:
128/x=100%/51%
6. Now we just have to solve the simple equation, and we will get the solution we are looking for.

7. Solution for what is 51% of 128

128/x=100/51
(128/x)*x=(100/51)*x - we multiply both sides of the equation by x
128=1.96078431373*x - we divide both sides of the equation by (1.96078431373) to get x
128/1.96078431373=x 
65.28=x 
x=65.28

now we have: 
51% of 128=65.28

8 0

3 years ago

Please help me with this! show that {1,2} ⊆ {x|x^4 - x^3 - x^2 - 5x + 6 = 0}

Llana [10]

The set $\{x\mid x^4-x^3-x^2-6x+6=0\}$ is the set of all values of $x$ that are solutions to the given equation. So all you need to do is check whether $x=1$ and $x=2$ satisfy the equation.

$x=1\implies 1^4-1^3-1^2-5+6=0$

$x=2\implies2^4-2^3-2^2-10+6=0$

The equation holds, so both 1 and 2 are solutions, and hence $\{1,2\}$ is a subset of the solutions.

6 0

3 years ago