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hram777 [196]
3 years ago
8

Which of the following might cause chronic hemorrhagic anemia?

Biology
1 answer:
Ulleksa [173]3 years ago
5 0

Answer:

c

Explanation:

a bleeding ulcer -  chronic hemorrhagic anemia depends a lot on  the volume and speed of blood loss

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Which of the following shows all of the tripeptides that can be formed from one molecule each of lysine (Lys), threonine (Thr),
Ierofanga [76]

Answer:

LysThrHis, LysHisThr, HisLysThr, HisThrLys, ThrLysHis, ThrHisLys

Explanation:

You easily combine the options for the tripeptide if you made a chart

Also you can calculate the posibilities with the factorial function in the calculatio (x!): 3*2*1 (you can multiplicate the number of amoniacids by the followed numbers until 1) = 6

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3 years ago
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ziro4ka [17]

Answer:

The discovery of the Double Dna Helix was done by Watson and Crick.

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What is the main purpose of oxygen of glucose in the body?
scoray [572]
Oxygen is required for aerobic respiration. This reaction produces ATP (universal currency for energy) which our bodies use to survive. Without oxygen much less ATP is produced, as aerobic respiration cannot occur in the lack of oxygen. ATP can be formed by anaerobic respiration, in the lack of oxygen, but this produces far far fewer molecules of ATP. This also produces lactic acid causing us to become fatigued and tired. Thus oxygen is crucial to produce the maximum amount of ATP possible.  

Glucose is the main molecule which is respired by our bodies to produce ATP/ energy, which our bodies use to survive. Oxygen and glucose react in the mitochondria to make ATP (release energy.) It therefore, is called a respiratory substrate.

Note: I'm avoided talking about the exact phases of respiration as it is usually not covered till college/ A level standards. If you would like to know exactly which reaction requires oxygen and how it's used (i.e. the stages of respiration) don't hesitate to ask. 
8 0
3 years ago
The cell will enter the G1 phase. During this phase, proteins and nucleotides needed for DNA replication will be produced. Also,
kolbaska11 [484]

Answer and Explanation:

The interphase is the previous step before mitosis occurs. The interphase is conformed of the G1, S, and G2 stages.

  • During the G1 stage, it occurs a high intense biochemical activity. The cell duplicates its size, and the organelles and other molecules and cytoplasmatic structures duplicate too. Some structures, such as microtubules and actin filaments, are synthesized from zero. The endoplasmic reticulum increases in size and produces a membrane for the Golgi apparatus and vacuoles, lysosomes, and vesicles. During this stage, the pair of centrioles separate, and each centriole duplicates. Mitochondria and chloroplasts also replicate.

The stages S and G2 follow the G1. Once the whole interphase is completed, mitosis occurs.

  • During the S stage occurs the DNI replication process. At this point, it also occurs the synthesis of histones and other associated proteins. This is the only stage where the DNI molecule is replicated.
  • G2 stage is the final one before the cellular division. Here it begins the slow process of DNI condensation. Duplication of centrioles completes. Structures such as spindle fibers are assembled.
5 0
3 years ago
Tallness (T) in snapdragons is dominant to dwarfness (t), and red (R) flower color is dominant to white (r). The heterozygous co
laila [671]

Answer:

E. 6:3:3:2:1:1

Explanation:

Look at the attached picture to see the Punnett square for your problem.

The cross for this is snapdragons who are heterozygous for both traits so the cross would be:

<em>TtRr x TtRr</em>

As you can see in the image, you have the following genotype combinations with the corresponding phenotype combinations:

GENTOTYPE       PHENOTYPE            NUMBER

TTRR                    Tall - Red                        1

TtRR                     Tall - Red                        2

TTRr                     Tall - Pink                       2

TtRr                      Tall - Pink                       4

TTrr                      Tall - White                     1

Ttrr                       Tall - White                     2

ttRR                      Short - Red                     1  

ttRr                       Short - Pink                    2

ttrr                        Short - White                  1

The following phenotype combinations in summary would then be:

Tall - Pink:     6

Tall - Red:      3

Tall - White:   3

Short - Pink:   2

Short - White: 1

Short - Red:   1

So the ratio is 9:3:3:2:1:1

7 0
3 years ago
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