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Archy [21]
3 years ago
6

Mikayla and Weatha went to the candy store and each spend the same amount of money to make party favor bags. Mikayla bought a pa

ckage of bags for $6.25 and 75 small pieces of candy. Weatha bought a package of bags for $4.75 and 90 small pieces of candy. How much does a small piece of candy cost?
Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
7 0

Answer:

$0.1

Step-by-step explanation:

From the information given, you know that Mikayla and Weatha spent the same amount of money and because of that you can write the following:

6.25+75x=4.75+90x, where x is the price of a small piece of candy

Now, you can solve for x:

6.25-4.75=90x-75x

1.5=15x

x=1.5/15

x=0.1

According to this, the answer is that a small piece of candy costs $0.1.

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Which statements about the graph of the function f(x) = -2- 4x + 2 are true? Select three options
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Answer:Its B,C, and E man

Step-by-step explanation:

5 0
2 years ago
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If f(x) = 9x10 tan−1x, find f '(x).
djverab [1.8K]

Answer:

\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}

General Formulas and Concepts:

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Derivative Property [Multiplied Constant]:                                                           \displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)  

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]:                                                                             \displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle f(x) = 9x^{10} \tan^{-1}(x)

<u>Step 2: Differentiate</u>

  1. [Function] Derivative Rule [Product Rule]:                                                   \displaystyle f'(x) = \frac{d}{dx}[9x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]
  2. Rewrite [Derivative Property - Multiplied Constant]:                                  \displaystyle f'(x) = 9 \frac{d}{dx}[x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]
  3. Basic Power Rule:                                                                                         \displaystyle f'(x) = 90x^9 \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]
  4. Arctrig Derivative:                                                                                         \displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

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3 years ago
Simplify (b^4)^3 A.B^9 B.B^3 C.B D.B^12
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(b^4)^3


To simplify when something is raised to two different exponents, multiply the two exponents together:

4 * 3 = 12

You now have b^12.


The answer is D.


6 0
3 years ago
How would I solve 11/15 + 3/10 with work please?!
AnnyKZ [126]
First you need to find a common denominator. 11/15 = 22/30

3/10= 9/30

9/30+22/30= 1 1/30

Hope this helps!
7 0
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Answer:

x:8/3

y:-2

Step-by-step explanation:

8 0
3 years ago
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