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3 years ago

What is 5.76 rounded to the nearest tenth?

Mathematics

2 answers:

Llana [10]3 years ago

7 0

Answer:

5.76 rounded to the nearest tenth is 5.8 or 5.80.

olga55 [171]3 years ago

5 0

The answer is 5.8 or 5.80

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Please help me really quick! :DD

shutvik [7]

Answer:

Correct equation: 4b^2 -b-138= 0

Solution: 6 meters

Step-by-step explanation:

The base has to be 6, and that’s the equation that works with that number.

8 0

3 years ago

The quotient of m and 7

pochemuha

The expression would me m / 7 or m and 7 as a fraction. M is on the top

6 0

3 years ago

Jack is flying his kite . He runs 100 feet away from his house and lets out 45 feet of string . The angle of elevation from the

fiasKO [112]

Answer: 125.80 ft

Step-by-step explanation:

Asuming the described situation is as shown in the figure below, we need to find the distance $h$ between the kite and Jacks house, but first we need to find the $x$ , $y$ and then $d$ .

How?

We will use trigonometry, especifically the trigonometric functions sine and cosine:

For $y$ :

$sin(65 \°)=\frac{y}{45 ft}$ (1)

Where $y$ is the opposite side to the angle and $45 ft$ the hypotenuse.

Isolating $y$ :

$y=40.78 ft$ (2)

For $x$ :

$cos(65 \°)=\frac{x}{45 ft}$ (3)

Where $x$ is the adjacent side to the angle.

Isolating $x$ :

$y=19.017 ft$ (4)

Finding $d$ :

$d=x+100 ft$ (5)

$d=19.017 ft +100 ft$

$d=119.017 ft$ (6)

Now that we have found these values, we have to work with a bigger triangle, where the hypotenuse is the distance between the kite and Jack's house $h$ and the sides are the values calculated in (4) and (6).

So, in this case we will use the <u>Pithagorean theorem</u>:

$h^{2}=y^{2} +d^{2}$ (7)

Isolating $h$ and writing with the known values:

$h=\sqrt{y^{2} +d^{2}}$ (8)

$h=\sqrt{(19.017 ft)^{2} +(119.017 ft)^{2}}$ (9)

$h=125.80 ft$ This is the distance between the kite and the house

3 0

3 years ago

Mark is creating a tarp to cover his new vegetable garden outside. He needs enough nylon to cover the garden which is 10 feet by

Cerrena [4.2K]

Answer:

$91.67.

Step-by-step explanation:

We have been given that Mark is creating a tarp to cover his new vegetable garden outside. He needs enough nylon to cover the garden which is 10 feet by 8 feet and then he will attach rope along the edges of the nylon to stake it down with.

A. Let us find area covered by nylon by multiplying 10 by 8.

$\text{ Amount of Nylon needed to cover the garden}=10\text{ feet}*8\text{ feet}$

$\text{ Amount of Nylon needed to cover the garden}=80\text{ feet}^{2}$

Now let us convert area of needed nylon from square feet into square yard by multiplying 80 by 0.111111.

$\text{ Amount of Nylon needed to cover the garden}=80*0.111111\text{ yards}^{2}$

$\text{ Amount of Nylon needed to cover the garden}=8.88889\text{ yards}^{2}$

Now let us multiply 8.88889 by 5.25 to find the cost of nylon cover of the garden.

$\text{ Cost of Nylon cover of the garden}=8.88889*5.25$

$\text{ Cost of Nylon cover of the garden}=46.6666725\approx 46.67$

Therefore, the cost of nylon cover will be $46.67.

B. Now let us find length of rope by finding the perimeter of the garden.

$\text{Length of rope}=2(10+8)\text{ feet}$

$\text{Length of rope}=2(18)\text{ feet}$

$\text{Length of rope}=36\text{ feet}$

Now let us find the cost of 36 feet long rope by multiplying 36 by 1.25.

$\text{Cost of rope}=36*1.25$

$\text{Cost of rope}=45$

Therefore, the cost of rope will be $45.

To find the total cost to make the cover we will add cost of nylon cover and cost of rope.

$\text{Total cost to make the cover}=45+46.67$

$\text{Total cost to make the cover}=91.67$

Therefore, it will cost $91.67 for Mark to make the cover for vegetable garden.

7 0

3 years ago

What is the area of a parallelogram ABCD

svetoff [14.1K]

Answer:

Area of a parallelogram would be 13.46

Step-by-step explanation:

Since area of a parallelogram is represented by the formula

Area = $\frac{1}{2}$ ( $(D_{1}*D_{2})$

Where $D_{1}$ and $D_{2}$ are two diagonals of the given parallelograms.

In the given figure $D_{1}=AC$ and $D_{2}$ = BD

We will find the length of $D_{1}$ and $D_{2}$ first

Since points A and C are (3,6) and (5,1)

So distance AC = $\sqrt{(6-1)^{2}+(3-5)^{2} }$

= $\sqrt{5^{2}+(-2)^{2}}$

= $\sqrt{25+4}=\sqrt{29}$

Since B and D are the points (6, 5) and (2, 2)

So length of BD = $\sqrt{(6-2)^{2}+(5-2)^{2}}$

BD = $\sqrt{4^{2}+3^{2}}=\sqrt{25}=5$

Now we will put these values in the formula

Area of parallelogram = $\frac{1}{2}(\sqrt{29})(5)$

= $\frac{5}{2}$ × $\sqrt{29}$

= (2.5) (5.385)

= 13.46

5 0

3 years ago