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3 years ago

Matthew drove 8/16 of the way to Kentucky and Fred drove the other 1/2 distance of the distance who drove the most

Mathematics

2 answers:

nydimaria [60]3 years ago

7 0

They both drove the same cause 8/16 is equal to 1/2

Leviafan [203]3 years ago

4 0

Both drove the same distance because you can draw a picture and you see its equal

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Solve for x. 3 - |8x-6I = 3 x= or x=

Ket [755]

Answer:

¾ = x

Step-by-step explanation:

Since 3 - 0 gives us the 3, we do this:

$0 = -|8x - 6|$

0 = -8x + 6 >> Distributive Property

-6 - 6

___________

-6 = -8x

__ ___

-8 -8

¾ = x

I am joyous to assist you anytime.

7 0

3 years ago

Five times the sum of the digits of a two-digit number is 13 less than the original number. If you reverse the digits in the two

mafiozo [28]

Answer:

The difference of the original two-digit number and the number with reversed digits is 18.

Step-by-step explanation:

Since it's a two digit number, let x represent the tens digit and let y represent the units digit.

Thus, the original two digit number is;

10x + y.

The reverse two digit number is;

10y + x.

We are told that five times the sum of the digits of the two-digit number is 13 less than the original number.

Thus;

5(x + y) = (10x + y) - 13

Multiplying out the bracket gives;

5x + 5y = 10x + y - 13

Rearranging gives;

10x - 5x + y - 5y = 13

5x - 4y = 13 - - - - (3)

Also,we are told that, four times the sum of its two digits is 21 less than the reversed two-digit number. Thus;

4(x + y) = (10y + x) - 21 - - - (4)

Simplifying gives;

4x + 4y = 10y + x - 21

>> 10y - 4y - 4x + x = 21

>> 6y - 3x = 21 - - - (4)

Solving eq(3) and (4) simultaneously gives;

x = 5 and y = 3

Thus,

Original number = 53

Reversed number = 35

Difference between original and reversed number = 53 - 35 = 18

6 0

3 years ago

The mean work week for engineers in start-up companies is claimed to be about 64 hours with a standard deviation of 8 hours. Kar

blondinia [14]

Answer:

1.) mean

2.) H0 : μ = 64

3.) 0.0028

4) Yes

Step-by-step explanation:

Null hypothesis ; H0 : μ = 64

Alternative hypothesis ; H1 : μ < 64

From the data Given :

70; 45; 55; 60; 65; 55; 55; 60; 50; 55

Using calculator :

Xbar = 57

Sample size, n = 10

Standard deviation, s = 7.14

Test statistic :

(xbar - μ) ÷ s/sqrt(n)

(57 - 64) ÷ 8 / sqrt(10)

Test statistic = - 2.77

Pvalue = (Z < - 2.77) = 0.0028 ( Z probability calculator)

α = 10% = 0.1

Reject H0 ; if P < α

Here,

P < α ; Hence, we reject the null

6 0

3 years ago

Answer this question for me ASAP PLEASE. Please show all work.

ziro4ka [17]

9514 1404 393

Answer:

acute scalene triangle

Step-by-step explanation:

The largest angle is acute, and all sides are different lengths. The triangle is an acute scalene triangle.

____

The magnitudes of the coordinate differences are ...

WX = (7, 5), XY = (2, 7), WY = (9, 2)

The two sides that are closest in length are ...

WX = √(49+25) = √74

WY = √(81 +4) = √85

Obviously, these are different lengths.

You can get a clue by comparing the numbers whose squares you are adding:

7^2 +5^2 > 7^2 +2^2 . . . . . WX > XY

9^2 +2^2 > 7^2 +2^2 . . . . WY > XY

so, the only question is relation between WX and WY. We note that the length of WX is less than one of the coordinate differences of WY, so we know WY is the longest. (√74 < 9)

We can tell from the graph that angle X (opposite longest side WY) is an acute angle, so the triangle is acute.

7 0

3 years ago

A common inhabitant of human intestines is the bacterium Escherichia coli. A cell of this bacterium in a nutrient-broth medium d

nikitadnepr [17]

Answer:

a) k=2.08 1/hour

b) The exponential growth model can be written as:

$P(t)=Ce^{kt}$

c) 977,435,644 cells

d) 2.033 billions cells per hour.

e) 2.81 hours.

Step-by-step explanation:

We have a model of exponential growth.

We know that the population duplicates every 20 minutes (t=0.33).

The initial population is P(t=0)=58.

The exponential growth model can be written as:

$P(t)=Ce^{kt}$

For t=0, we have:

$P(0)=Ce^0=C=58$

If we use the duplication time, we have:

$P(t+0.33)=2P(t)\\\\58e^{k(t+0.33)}=2\cdot58e^{kt}\\\\e^{0.33k}=2\\\\0.33k=ln(2)\\\\k=ln(2)/0.33=2.08$

Then, we have the model as:

$P(t)=58e^{2.08t}$

The relative growth rate (RGR) is defined, if P is the population and t the time, as:

$RGR=\dfrac{1}{P}\dfrac{dP}{dt}=k$

In this case, the RGR is k=2.08 1/h.

After 8 hours, we will have:

$P(8)=58e^{2.08\cdot8}=58e^{16.64}=58\cdot 16,852,338= 977,435,644$

The rate of growth can be calculated as dP/dt and is:

$dP/dt=58[2.08\cdot e^{2.08t}]=120.64e^2.08t=2.08P(t)$

For t=8, the rate of growth is:

$dP/dt(8)=2.08P(8)=2.08\cdot 977,435,644 = 2,033,066,140$

(2.033 billions cells per hour).

We can calculate when the population will reach 20,000 cells as:

$P(t)=20,000\\\\58e^{2.08t}=20,000\\\\e^{2.08t}=20,000/58\approx344.827\\\\2.08t=ln(344.827)\approx5.843\\\\t=5.843/2.08\approx2.81$

3 0

3 years ago