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MaRussiya [10]
3 years ago
6

Write an expression to represent the area of a rectangle if the length of a rectangle is three units more than its width

Mathematics
1 answer:
Vitek1552 [10]3 years ago
5 0
We can call the width “x”. Since the length is three units more than its width, we can call the length “x+3”.

Thus, the area is x(x+3), which simplifies to x^2+3x.
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faust18 [17]
The numbers divisible by 3 are multiples of 3.
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A girl is 18 years old and her brother is a third of her age. When the girl is 36 what would be the age of the brother?
ale4655 [162]
First we need to calculate how many years her brother has when she is 18. As text says he is:
18/3 = 6 years old

Now when she gains another 18 years (36-18=18) he will also gain those 18 years

When she is 36 he will have 6+18=24 years old

Answer is 24.
8 0
3 years ago
Read 2 more answers
Please solve<br><br> ??-3/10=1/5
lina2011 [118]

Answer:

5

Step-by-step explanation:

5-3=2

2/10=1/5

6 0
2 years ago
Read 2 more answers
PLEASE HELP.
krek1111 [17]

Answer:

Part a) The radii are segments AC and AD and the tangents are the segments CE and DE

Part b) DE=4\sqrt{10}\ cm

Step-by-step explanation:

Part a)

we know that

A <u>radius</u> is a line from any point on the circumference to the center of the circle

A <u>tangent</u> to a circle is a straight line which touches the circle at only one point. The tangent to a circle is perpendicular to the radius at the point of tangency.

In this problem

The radii are the segments AC and AD

The tangents are the segments CE and DE

Part b)

we know that

radius AC is perpendicular to the tangent CE

radius AD is perpendicular to the tangent DE

CE=DE

Triangle ACE is congruent with triangle ADE

Applying the Pythagoras Theorem

AE^{2}=AC^{2}+CE^{2}

substitute the values and solve for CE

14^{2}=6^{2}+CE^{2}

CE^{2}=14^{2}-6^{2}

CE^{2}=160

CE=\sqrt{160}\ cm

CE=4\sqrt{10}\ cm

remember that

CE=DE

so

DE=4\sqrt{10}\ cm

7 0
3 years ago
The area A, in square meters, of a rectangle with a perimeter of 160 meters is given by the equation A = 80w − w2, where w is th
Sonja [21]

Answer:

the width is 10 m

Step-by-step explanation:

if the relationship between area and width is

A = 80*w − w²

for an area A=700 m² , we have

700 m² = 80*w − w²

w² - 80*w + 700 m² = 0

aw² + b*w + c = 0

where a=1 , b=-80 and c=700

this quadratic equation has as solution the following formula

w = [-b ± √ ( b² - 4*a*c) ]/(2*a)

replacing values

w = [80 ± √ ( 80² - 4*1*700) ]/(2*1) = (80 ± 60)/2

then

w₁=(80 - 60)/2 = 10 m

w₂ =(80 + 60)/2 = 70 m

since the area has the form A= length * width = 80*w − w² = (80− w)*w

then the length of the rectangle is

length = 80− w

for w₁=10 m → length = 80− 10 = 70 m

for w₁=70 m → length = 80− 70 = 10 m

by definition the shorter side is the width ( and the longer one , the length) , therefore the only possible option is the first one .

Thus the width is 10 m

7 0
3 years ago
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