12, 2, 4, and 7. The coefficients in the expression 12xy³+2x⁵y+4x⁵y²+7x⁵y are 12, 2, 4, and 7.
In order to solve this problem we have to know that the coefficients is a factor linked to a monomial. For example, the first monomial of the equation is 12xy³ the coeffcient of xy³ is 12.
A co-efficient is behind a monomial, like if we had 5x, 5 is the co efficient, if we had just x, we know that x is actually 1x, here we have 12,2,4, and 7. Hope this helps
