Let
be the random variable for the number of marks a given student receives on the exam.
10% of students obtain more than 75 marks, so

where
follows a standard normal distribution. The critical value for an upper-tail probability of 10% is

where
denotes the CDF of
, and
denotes the inverse CDF. We have

Similarly, because 20% of students obtain less than 40 marks, we have

so that

Then
are such that


and we find

3sinx+1=sinx
2sinx+1=0
2sinx=-1
sinx=-1/2
x=sin^-1 (1/2) = 30 =

/6 (when finding the inverse, always take the positive value, ignore the negative sign)
x is therefore negative in 3rd and 4th quadrant
Therefore values of x are:
180+30=210 = 7

/6
360-3=330 = 11

/6
Answer:
Written Below.
Step-by-step explanation:
A system of linear equations has one solution when the graphs intersect at a point. A system of linear equations has no solution when the graphs are parallel. A system of linear equations has infinite solutions when the graphs are the exact same line.
(This uses graphing.)
Sidenote: I hope this helps! :)
5/8 = 0.625 = 62.5%
If 62.5% were glazed then you must find 62.5% of 24.
Equation…
x=0.625(24) = 15
if each costs $0.84 cents plus tax then you will multiply by 15.
15 x .84 = 12.6
The total cost was $12.60
A. The equation to find the distance of the flowerbed from the hive is:
, where x is the distance.
B. The flowerbed is 2250 feet far from the hive.
<u><em>Explanation</em></u>
Suppose, the distance of the flowerbed from the hive is
feet.
The bee flies 20 feet per second directly to a flowerbed from its hive and flies directly back to the hive at 12 feet per second.
As,
So, the time taken by the bee to reach the flowerbed
seconds and the time taken to fly back to the hive
seconds.
The bee stays at the flowerbed for 15 minutes or (15×60)seconds or 900 seconds and it is away from the hive for a total of 20 minutes or (20×60)seconds or 1200 seconds.
So, the equation will be.......

Thus, the distance of the flowerbed from the hive is 2250 feet.