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3 years ago

Somebody plz help me this is due tomorrow plzz!!!!

Mathematics

1 answer:

Eddi Din [679]3 years ago

4 0

For number one if you add up the numbers in each square you’ll notice each square is the same sum. You can use a similar strategy for number two.

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A bag contains 4 red marbles, 3 white marbles, and 7 blue marbles. You pick a marble without looking. Find the probability of dr

astra-53 [7]

The probability of drawing a white marble = $\frac{Number of white marbles}{Total number of Marbles}$

∴ the probability of drawing a white marble = ³/₁₄

6 0

3 years ago

PlZz answer i need HELP ANswer BOth

KatRina [158]

Answer:

$m = 35.65 \\ b = 17.25$

Step-by-step explanation:

srry if its wrong but I think it's right :)

btw for the first one

p=19.53

8 0

3 years ago

Andy estimated that he would need 75 feet of lumber for a tree house project. he later found that the actual amount of lumber ne

Kipish [7]

Step 1
<span>Calculate the error
</span>error=75-64-----> 11 ft

step 2
<span>Divide the error by the exact value
</span>11/64=0.1719

step 3
<span>Convert that to a percentage
</span>0.1719*100=17.19%

the answer is
17.19%

8 0

3 years ago

A first number plus twice a second number is 11. Twice the first number plus the second totals 16. Find the numbers.

satela [25.4K]

<h3><u>The first number, x, is equal to 7.</u></h3><h3><u>The second number, y, is equal to 2.</u></h3>

x + 2y = 11

2x + y = 16

We can subtract 2y from both sides of the first equation to get a value for x.

x = 11 - 2y

Because we have a value for x, we can plug it into the second equation.

2(11 - 2y) + y = 16

Distributive property.

22 - 4y + y = 16

Combine like terms.

22 - 3y = 16

Subtract 22 from both sides.

-3y = -6

Divide both sides by -3.

y = 2

Now that we have a value for y, we can plug it into either equation to solve for x.

x + 2(2) = 11

x + 4 = 11

Subtract 4 from both sides.

x = 7

4 0

3 years ago

What is the discontinuity and zero of the function f(x) = 3x^2 + x - 4 / x-1

7nadin3 [17]

Ans: Option (1) <span>Discontinuity at (1, 7), zero at ( negative four thirds , 0)
</span>
Explanation:
Given function:
$f(x) = \frac{3x^2 + x - 4}{x-1}$

Now if we plug in the x = 1, we would have discontinuity as function goes to infinity.

Now for f(1):
$f(x) = \frac{3x^2 + x - 4}{x-1} \\ f(x) = \frac{3x^2 + 4x - 3x - 4}{x-1} \\ f(x) = \frac{x(3x+4)-1(3x+4)}{x-1} \\ f(x) = \frac{(x-1)(3x+4)}{(x-1)} \\ f(x) = 3x+4 \\ now ~ insert ~ x=1: \\ f(1) = 3(1) + 4 = 7 \\ It~means~discontinuity~at~(1,7).\\ Now~let~us~find~zeros.\\ put~ f(x) = 3x+4 ~ equals~ to ~zero. \\ =\ \textgreater \ ~3x+4 = 0 \\ =\ \textgreater \ ~ x = \frac{-4}{3} \\ Hence~zeros=( \frac{-4}{3}, 0)$

5 0

3 years ago

Somebody plz help me this is due tomorrow plzz!!!!​

Somebody plz help me this is due tomorrow plzz!!!!