The cost can be optimized by using a Linear Programming given the linear constraint system
- To minimize the cost, the biologist should use <u>60 samples of Type I</u> bacteria and <u>0 samples of Type II</u> bacteria
Reason:
Let <em>X</em> represent Type 1 bacteria, and let <em>Y</em>, represent Type II bacteria, we have;
The constraints are;
4·X + 3·Y ≥ 240
20 ≤ X ≤ 60
Y ≤ 70
P = 5·X + 7·Y
Solving the inequality gives;
4·X + 3·Y ≥ 240
(Equation for the inequality graphs)
The boundary of the feasible region are;
(20, 70)
(20, 53.
)
(60, 0)
(60, 70)
The cost are ;
![\begin{array}{|c|c|c|}X&Y&P= 5\times X + 7 \times Y\\20&70&590\\20&53.\overline 3&473.\overline 3\\60&0&300\\60&70&790\end{array}\right]](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7B%7Cc%7Cc%7Cc%7C%7DX%26Y%26P%3D%205%5Ctimes%20X%20%2B%207%20%5Ctimes%20Y%5C%5C20%2670%26590%5C%5C20%2653.%5Coverline%203%26473.%5Coverline%203%5C%5C60%260%26300%5C%5C60%2670%26790%5Cend%7Barray%7D%5Cright%5D)
- Therefore, the minimum cost of $300 is obtained by using <u>60 samples of Type I</u> and <u>0 samples of Type II</u>
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brainly.com/question/17646656
Answer:
1) The variable is x
2)
Solving the inequality we get x>34
3)
, solving the inequality we get b>10.2
Step-by-step explanation:
1. Define the variable:
The variable is x
2) Trini needs more than 51 cubic feet of soil to top up his raised garden. Each bag of soil contains 1.5 cubic feet. Write and solve an inequality to find how many bags of soil Trini needs.

Solving the inequality

Solving the inequality we get x>34
3) Write the inequality:
5 times b greater than 51

4) Solving the inequality

So, solving the inequality we get b>10.2
9514 1404 393
Answer:
2.49×10^7
Step-by-step explanation:
14,200,000 +10,700,000 = 24,900,000 = 2.49×10,000,000
= 2.49×10^7
_____
Your scientific or graphing calculator can tell you the sum and display it in scientific notation.
Answer:
see explanation
Step-by-step explanation:
The surface area (A) of a sphere is calculated as
A = 4πr² ← r is the radius, here r = 9, thus
A = 4π × 9² = 4π × 81 = 324π ≈ 1017.9 units²