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2 years ago

6

The balance sheet contains these three elements of a business

1 answer:

Art [367]2 years ago

8 0

Answer:

The balance sheet consists of three major elements: assets, liabilities and owners' equity. The object of the statement is to prove true the accounting equation, "Asset = Liabilities + Owner's Equity."

Hope this helps!! :)

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Brooke says there are 49 days until 4th of July. There are 7 days in a week. In how many days will it be 4th of July??

nignag [31]

In real life, there are 35 days until the 4th of July.

In the problem, if Brooke is correct, there are 49 days until the 4th of July.

This question is weird.

7 0

3 years ago

Read 2 more answers

A new truck costs $32,000 if the truck is worth 24,500 after three years write an explicit formula for the value of the car afte

Debora [2.8K]

Answer:

Step-by-step explanation:

depreciation for three years = 32000 - 24500 = $ 7500

depreciation per year = 7500/3 = $ 2500

depreciation % = (2500/32000)*100 = 7.81%

Value of truck after n years = 32000 * (7.81%)*n

8 0

3 years ago

Hey! i’ll give brainliest please help.

dexar [7]

The last name I am pretty sure of it.

7 0

2 years ago

Read 2 more answers

Which option lists am expression that is not equivalent to 4^2/3

Vesnalui [34]

remember that

$x^{\frac{a}{b}}=\sqrt[b]{x^a}$

also $x^{-a}=\frac{1}{x^a}$

and $(a^b)^c=a^{bc}$

so

$4^{\frac{2}{3}}$

first one, that one is clearly not equal since 0.25≠4

2nd one, 0.25=1/4, so $0.25^{\frac{-2}{3}}=(\frac{1}{4})^{\frac{-2}{3}=$ $\frac{1}{(\frac{1}{4})^{\frac{2}{3}}}=4^{\frac{2}{3}}$ , which matches

3rd one, $\sqrt[3]{16}=\sqrt[3]{4^2}=4^{\frac{3}{2}}$ , which matches

4th one $(\sqrt[3]{4})^2=(4^{\frac{1}{3}})^2=4^{\frac{2}{3}}$ which matches

answer is $0.25^{\frac{2}{3}}$

4 0

3 years ago

Diagram 2 shows a piece of rectangular card in grey colour

Ilya [14]

Solution:

we have given the length of the rectangular card-

$x + 5 \: cm$

and, width-

$7 \: cm$

now, the area of the card will be- length×width.

so, we have-

$(x + 5) \times 7 \: cm^{2} \\ 7x + 35 \: cm^{2}$

we also have given the length of ribbon-

$7 \: cm$

and, width-

$y \: cm$

so, area of the ribbon is-

length×width

$7 \times y \: cm^{2} \\ 7y \: cm^{2}$

now the area of shaded gray region will be-

$7x + 35 - 7y$

Hence, the required expression would the above expression.

6 0

2 years ago