The formula we need is

, where <em>v</em>₀ is the starting velocity and <em>h</em>₀ is the initial height. Using the velocity and starting height from our problem we have

. The path of this rocket will be a downward facing parabola, so there will be a maximum. This maximum will be at the vertex of the graph. To find the vertex we start out with

, which in our case is

. It will take 5 seconds for the rocket to reach its maximum height. Plugging this back into our formula gives us

The rocket's maximum height is 400 feet.
We set our formula equal to zero to find the time it takes to hit the ground, then we factor:

Using the zero product property, we know that either -16t =0 or t-10=0. When -16t=0 is at t=0, when the rocket is launched. t-10=0 gives us an answer of t=10, so the rocket reaches the ground again at 10 seconds.
Number 1 is A.Q and S because if you flip the shape around the degrees will be the same
Number is 42 degrees if you multiple 42•2 is 84-26 is 58 and 42 plus 16 is 58 which are equal if you substitute any of the other choices it will not be equal
x^2 - 3x -28 ≥ 0
factor
(x-7) (x+4) ≥ 0
x=7 x=-4
we have three regions where the answers can lie
x<-4 between -4 and 7 and x>7
pick a point and see if it works
x=-10
(-10-7) (-10+4) ≥ 0
negative * negative is greater than 0 so this is a solution x< -4
x=0
(0-7) (+4) ≥ 0
negative * positive is less than 0 so this is not a solution
x=10
(10-7) (10+4) ≥ 0
positive * positive is greater than 0 so this is a solution x>7
We have two regions that work
x<-4 and x>7
Kilometers to Miles:
For an approximate result, divide the length value by 1.609
Answer:
C.
Step-by-step explanation: