Question

The following data represent the flight time​ (in minutes) of a random sample of seven flights from one city to another city. 281​, 269​, 259​, 265​, 256​, 259​, 266 Compute the range and sample standard deviation of flight time. The range of flight time is 25 minutes. The sample standard deviation of flight time is nothing minutes.

Answer 1

Answer:

$Range = 281-256= 25$

In order to calculate the sample deviation we need to calculate the mean given by:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

And replacing we got:

$\bar X= 265$

And the standard deviation can be calculated with this formula:

$s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And replacing we got:

$s = 8.426$

Step-by-step explanation:

For this case we have the following data given:

281​, 269​, 259​, 265​, 256​, 259​, 266

The range is defined as:

$Range = Max -Min$

And if we replace we got:

$Range = 281-256= 25$

In order to calculate the sample deviation we need to calculate the mean given by:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

And replacing we got:

$\bar X= 265$

And the standard deviation can be calculated with this formula"

$s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And replacing we got:

$s = 8.426$