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True [87]
3 years ago
15

There are 1,345 students in the school. The entire school is going on a field trip and needs to fit on buses that hold 55 studen

ts. How many buses will be needed?
Mathematics
1 answer:
Anestetic [448]3 years ago
7 0

Answer:1345/55=55

55buses will be needed

Step-by-step explanation:

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A container contains 12 diesel engines. The company chooses 5 engines at​ random, and will not ship the container if any of the
Rufina [12.5K]

Answer:\frac{^{10}C_5}{^{12}C_5}

Step-by-step explanation:

Given a total of 12 diesel engines

out of which 2 are defective

Company have to choose 5 good engines to ship.

Therefore no of ways in good engines are selected is ^{10}C_5

no of ways in which any 5 engines are selected from a total of 12 engines is

^{12}C_5

Therefore the required probability =\frac{^{10}C_5}{^{12}C_5}

=\frac{7}{22}=0.318

3 0
3 years ago
When a certain number is multiplied by 14 and the product is then multiplied by 32, the result is 60. what is the number?
Stolb23 [73]
It might be 0.133928571.....? I am unsure though. Sorry if this doesn't help
7 0
2 years ago
What is the middle of 1 and 6
devlian [24]

Answer:

The middle between two numbers is the average of those numbers. So we add those two numbers together and divide by two. And the answer is (1 + 6) / 2 = 3.5

5 0
2 years ago
Read 2 more answers
Find the 60th term of the arithmetic sequence 4,-1,-6-
kobusy [5.1K]

Answer:

-291

Step-by-step explanation:

The common difference is -5

So the 60th term of the arithmetic sequence is

4+(60-1)×-5

=4+59×-5

=4+-295

=-291

8 0
3 years ago
In a histogram, the proportion of the total area which must be to the left of the median is:
Lana71 [14]

Answer:

A. exactly 0.50

Step-by-step explanation:

We have been given a statement. We are asked to choose the correct option about given statement.

We know that every histogram has 5 points summary.

1st point is known as minimum point, 2nd point is first quartile, 3rd point is median, 4th point is upper quartile and 5th point is maximum point.

In a normal distribution 25% of the data points are to the left 1st quartile, 50% of the data points are to the left of median and 75% of the data points are to the left 2nd quartile.

50\%=\frac{50}{100}=0.50

Therefore, exactly 0.50 of the total area which must be to the left of the median.

6 0
3 years ago
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