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frez [133]
3 years ago
15

If you were to solve the following system by substitution, what would be the best variable to solve fro and from what equation?

Mathematics
1 answer:
Svetlanka [38]3 years ago
4 0
I would say solve for x in the second equation
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Find the solutions to the equation by completing the square.
rjkz [21]

Answer:

Step-by-step explanation:

hello :

x² - 6x = 7

x² - 6x+9-9___= 7

(x - 3 )²= __16_

x - 3= +/-_4__

x-3=4__and x-3 =_-4_

8 0
3 years ago
Answer choices:<br><br> y = x<br> y = 1/4x - 2<br> y = -x + 7/4<br> y = 7/4x - 2
kumpel [21]

Answer:

all in all it's y=x

Step-by-step explanation:

A (4,1); B (0,-2)

G=delta y

--------

delta x

1-(-2)

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4-0

3/4=G

3/4=y-1/x-4

4 (y-1)=3 (x-4)

4y-4=3x-12

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5 0
2 years ago
Solve this problem as quickly as you can
Oksi-84 [34.3K]
What is the expression though?
7 0
3 years ago
To find the coordinates of point L, the midpoint of JK, the equation M = can be used. What are the coordinates of point L? L(1,
anygoal [31]
Since we are already given with the formula to solve for the coordinates of point L, all we have to do is to perform the necessary operation in the item. The formula for the coordinates of the midpoint is,                    M = ((5 + 1) / 2 , (3 - 7) / 2)performing the operation,                   M = (3, -2)Thus, the coordinates of point L are (3,-2).
 Read more on Brainly - brainly.com/sf/question/2881337
8 0
2 years ago
Read 2 more answers
From a group of 20 day workers and 12 night workers, a skeleton work crew of 5 day workers and 3 night workers must be formed. i
wel

Answer:

3,410,880 ways.

Step-by-step explanation:

There are no markings to differentiate the position so the order is not important. The group also divided into day and night workers which independent from each other.

You want to make a schedule for 5 day workers out of 20 day workers, the number of ways to do that will be: 5C20= 20!/5!15! =15504 ways

You want to make a schedule for 3 night workers out of 12 night workers, the number of ways to do that will be: 3C12= 12!/3!9! =220 ways

The total number of ways possible will be 15504 * 220 = 3410880 ways.

5 0
3 years ago
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