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klio [65]
3 years ago
14

How do you solve the math equation y-y=m(x-x) for when you have to find the equation for an in and out table? i know how to get

the numbers and plug them in, but i dont know how to simplify it to get the actual equation for the in and out table.
Mathematics
2 answers:
S_A_V [24]3 years ago
7 0
What you do is you put the numbers into the equation subtract a number from both sides whatever you get from that you divide that with x
Luden [163]3 years ago
3 0
You first take any two points from the table and find the slope. Then you can take that slope and any point in the table and plug it into that point-slope form equation.

\sf y-y_1=m(x-x_1)

Where 'm' is the slope and \sf (x_1,y_1) is a point on the line(or in this case a point in the table).

You can then distribute the slope into the parenthesis and add/subtract y1 to both sides to get the slope-intercept form equation.
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4. Khup bought three cans of soda for $0.95 each. She paid
34kurt

Answer:

okay so if 3 cans are $.95 each she paid $2.85. She paid with $5.00. so 5-2.85 means she got <u>$2.15</u> back for her change

8 0
3 years ago
Read 2 more answers
A realtor would like to create a 95% confidence interval for the average price of a house in Franklin County, Ohio. To accomplis
VMariaS [17]

Answer:

320128-1.96\frac{50324}{\sqrt{529}}=315839.52    

320128+1.96\frac{50324}{\sqrt{529}}=324416.48    

So on this case the 95% confidence interval would be given by (315839.52;324416.48)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=320128 represent the sample mean

\mu population mean (variable of interest)

\sigma=50324 represent the population standard deviation

n=529 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that z_{\alpha/2}=1.96

Now we have everything in order to replace into formula (1):

320128-1.96\frac{50324}{\sqrt{529}}=315839.52    

320128+1.96\frac{50324}{\sqrt{529}}=324416.48    

So on this case the 95% confidence interval would be given by (315839.52;324416.48)    

8 0
3 years ago
Traders joes sold 7981 bags of tortilla chips recently. If 1178 of these bags were fat free find the percent that were fat free.
lawyer [7]

Answer:

14.76% of tortilla chips bag were fat free.  

Step-by-step explanation:

We are given the following in he question:

Number of bags of tortilla chips sold = 7981

Number of bags hat were fat free = 1178

We have to find the percentage of bags that were fat free.

Percentage:

\dfrac{\text{Number of fat free bags}}{\text{Total number of bags}}\times 100\%\\\\=\dfrac{1178}{7981}\times 100\%\\\\=14.76\%

Thus, 14.76% of tortilla chips bag were fat free.

4 0
3 years ago
What is 30 divided by 75 and show the work plz?
Anna007 [38]

Answer:

All Work is on the Paper.

Step-by-step explanation:

Glad to Help!

7 0
4 years ago
Where is the number 5 − 9 located on a horizontal number line? (1 point)
taurus [48]
9 units to the left of 5. 
3 0
3 years ago
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