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poizon [28]
3 years ago
10

Sara Blake's grandmother gave her $3000.00 to save for college. She put it in a savings account that earns 6% interest per year.

The money was in the account for 8 years.
Mathematics
1 answer:
zubka84 [21]3 years ago
6 0
I assume you are looking for the total. The total amount in the account will be $4,781.54 if the interest is compounded annually.

If she is earning 6% interest, the balance in her account will be multiplied by 1.06 each year.

You can evaluate the following expression to find the total.
3000(1.06)^8 = 4781.54
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Find m<br> A. 12<br><br> B. 22 <br><br> C. 52<br><br> D. 38
Nikolay [14]

C. 52

Work:

(5x - 22) + (4x + 4) = 90

9x - 18 = 90

9x = 108

x = 12

4(12) + 4 =

48 + 4 = 52

6 0
3 years ago
Which of the following correctly completes the square for the equation below?
erastova [34]
The answer is :

c. (x+1)²=20

To check:
(x+1)²=20                          (a+b)²=a²+2ab+b²
x²+2x+1=20
x²+2x=20-1
x²+2x=19
3 0
3 years ago
Read 2 more answers
BRAINIEST TO WHOEVER RIGHT
adoni [48]

Answer:

i know b only Sorry hope this helps tho

Step-by-step explanation:

its 4 because each space is 25% no matter how big or small it is. so if you land on -9 to -5 thats 25% and to -2 thats another 25% total 50% its asking for 75% so you go one more which lands on 4 making it 75%

5 0
3 years ago
Read 2 more answers
Suppose the standard deviation of a normal population is known to be 3, and H0 asserts that the mean is equal to 12. A random sa
blagie [28]

Answer:

z=\frac{12.95-12}{\frac{3}{\sqrt{36}}}=1.9  

p_v =P(z>1.9)=0.0287  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 12 at 5% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=12.95 represent the sample mean

\sigma=3 represent the population standard deviation for the sample  

n=36 sample size  

\mu_o =12 represent the value that we want to test  

\alpha=0.05 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is equal to 12, the system of hypothesis would be:  

Null hypothesis:\mu \leq 12  

Alternative hypothesis:\mu > 12  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{12.95-12}{\frac{3}{\sqrt{36}}}=1.9  

P-value  

Since is a right tailed test the p value would be:  

p_v =P(z>1.9)=0.0287  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 12 at 5% of signficance.  

4 0
3 years ago
Read 2 more answers
Can someone help me? ​
zimovet [89]

Answer:

61.538

Step-by-step explanation:

5 0
2 years ago
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