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Lostsunrise [7]
4 years ago
13

John's boss asks for a recommendation for connecting the company network to a small satellite building about 1 km from the main

campus. The company owns the verdant land in between. Given such a scenario, what network technology implementation should John suggest?
A. Ethernet over UTP
B. Ethernet over STP
C. Ethernet over multimode fiber
D. Ethernet over single-mode fiber
Computers and Technology
1 answer:
tresset_1 [31]4 years ago
4 0

Answer:

C. Ethernet over multi mode fiber .

Explanation:

Given that the distance to be covered is 1 km. Multi-mode optic fiber is best suited for short distances of up to 2 km and can withstand harsh environments with less signal attenuation. Single mode fiber is best suited long distance of up to 200 km or more and is expensive as compared to multi-mode fiber Ethernet over twisted pair is best for indoor use and can only cover very short distances. Although UTP and STP are relatively cheap they cannot withstand harsh environments without great signal loss.

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3 years ago
Read an integer from keyboard and then print the result of the sum obtained by adding the entered integer to the integer formed
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Answer:

Following are the program in C++ language

#include <iostream> // header file

using namespace std; //  namespace std;

int main() // main function

{

int number,n1,rem; // variable declaration

int sum,sum1=0;// variable declaration

cout<<"Enter the number :";

cin>>number;// Read the number

n1=number; // initialized the value of number with the n1

while(n1>0) // iteating the  while loop

{

   rem=n1%10; // finding the reminder

   sum1=10*sum1+rem;  // storing the sum

   n1=n1/10;

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sum=sum1+number; // calculate the sum

cout<<"The sum is:"<<sum; // Display sum

   return 0;

}

Output:

Enter the number :123

The sum is:444

Explanation:

Following are the Description of the Program

  • Read the value of "number" in the "number" variable of int type .
  • Initialized the value of "number" in the "n1' variable.
  • Iterating the while loop until the n1>0.
  • In this loop we reverse the number in the "sum1" variable
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Consider the two computers A and B with the clock cycle times 100 ps and 150 ps respectively for some program. The number of cyc
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Answer:

Option d) B is 1.33 times faster than A

Given:

Clock time, t_{A} = 100 ps

t_{A} = 150 ps

No. of cycles per instructions,  n_{A} = 2.0

n_{B} = 1.0

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Let I be the no. of instructions for the program.

CPU clock cycle, f_{A} = 2.0 I

CPU clock cycle, f_{B} = 1.0 I

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CPU time for each can be calculated as:

CPU time, T = CPU clock cycle\times clock time

T_{A} = f_{A}\times t_{A} = 2.0 I\times 100 = 200 I ps

T_{B} = f_{B}\times t_{B} = 1.0 I\times 100 = 150 I ps

Thus B is faster than A

Now,

\frac{Performance of A}{Performance of B} = \frac{T_{A}}{T_{B}}

\frac{Performance of A}{Performance of B} = \frac{200}{150}

Performance of B is 1.33 times that of A

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