I think that the answer is: A executable
Based on the Microsoft Excel data validation, the option that is not an Error Style for data validation is the <em><u>choice that does not show an error alert.</u></em>
Given that there is no option available, the best way to answer this question is to show the types of Error Styles for data validation available.
<h3>Different types of Error Style for data validation</h3>
- Stop style: this will bring the option of "Retry, " "Cancel, " and "Help."
- Warning style: this will show "Continue," with options of "Yes," "No," "Cancel," and "Help."
- Information Style: this will ask you to input the whole number with the option of "Ok," "Cancel," and "Help."
Hence, in this case, it is concluded that the Error Style for data validation is Stop, Warning, and Information Style.
Learn more about Error Style for data validation here: brainly.com/question/18497347
Answer:
B. Have the user press the appropriate function key combination to enable the wireless radio and then attempt to connect to the wireless network.
Explanation:
Every more often than not, users may experience wireless connection problems. How they respond to these issues solely depends on various factors. When a user like this has issues connecting to the network, first on the list of proper troubleshooting procedures is to check whether the wireless adapter or the function key that turns the wireless radio connection on is toggled on. Sometimes the most obvious causes are the hardest to see. The user should check this first because it will save him or her lots of troubleshooting time if the switch was simply physically disabled.
Answer:
import java.util.*;
public class MyClass {
public static void main(String args[]) {
Scanner input = new Scanner(System.in);
System.out.print("Input a word: ");
String userinput = input.nextLine();
for(int i =0;i<userinput.length();i+=2) {
System.out.print(userinput.charAt(i));
}
}
}
Explanation:
This line prompts user for input
System.out.print("Input a word: ");
This declares a string variable named userinput and also gets input from the user
String userinput = input.nextLine();
The following iterates through every other character of userinput from the first using iteration variable i and i is incremented by 2
for(int i =0;i<userinput.length();i+=2) {
This prints characters at i-th position
System.out.print(userinput.charAt(i));
