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koban [17]
3 years ago
15

Solve a triangle with a = 32. b = 38, and c = 46.

Mathematics
1 answer:
Aleksandr [31]3 years ago
6 0

Using the law of cosines:

Angle A

a^2 = b^2 + c^2 - 2 * b * c * cos(Angle A)

32^2 = 38^2 + 46^2 - 2 * 38 * 46 * cos(Angle A)

1024 = 1444 + 2116 - 3496 * cos(Angle A)

3496 * cos(Angle A) = 1444 + 2116 - 1024

3496 * cos(Angle A) = 2536

cos(Angle A) = 2536 / 3496

Angle A = arccos(2536 / 3496)

Angle A = 43.5 degrees.

Using the same steps calculate angle b and angle c ( rearrange the formula to have b^2 and c^2 equal to:

Angle b = 54.8 degrees

Angle C = 81.7 degrees.

The answer is A. A = 43.5°: B = 54.8°: C= 81.70

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Option A: >

Solution:

Given a triangle GHJ.

The line GH is perpendicular to line HJ.

This means the triangle is a right angled triangle.

In ΔGHJ, GH is the base of the triangle and

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We know that by the Pythagoras theorem,

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Option A: > is the correct answer.

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3 years ago
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Step-by-step explanation:

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