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3 years ago

I need help with the first one only please

Mathematics

2 answers:

Shtirlitz [24]3 years ago

7 0

0.3 should be the answer!

elena-s [515]3 years ago

4 0

On the top of the fraction will be a x because it means multiply u multiply 5 and 2 to get 10 that is how u get ur answer.

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a rectangle with width of 7 and length of 9 has a square of side length 5 cut out of it. what is the area of the rectangle after

dezoksy [38]

Area of rectangle is 7x9 which is 63
Area of the square=5x5 which is 25
So area is: 63-25=38

6 0

3 years ago

Which polynomial represents the sum below? (14x2 – 14) + (–10x2 – 10x + 10) A. 4x2 – 10x + 24 B. 4x2 – 10x – 4 C. 24x2 – 24x – 1

Gennadij [26K]

Answer:

answer : B

Step-by-step explanation:

(14x2 – 14) + (–10x2 – 10x + 10) = (14x² - 10x²) -10x + (-14+10)

(14x2 – 14) + (–10x2 – 10x + 10) = = 4x² - 10x - 4

answer : B

3 0

4 years ago

Read 2 more answers

19. Hairs found at a crime scene are consistent with those of a suspect.

Inessa [10]

First off this is an English question.
Second, the answer is: deductive reasoning.

Explanation: Deductive reasoning is thinking about and organizing facts and ideas in a logical way.

3 0

3 years ago

13-8+3 evaluate using the Order of Operation

Novay_Z [31]

You would just subtract/add like you normally would from left to right because its a subtract and add operation.

Hope that helps :)

6 0

4 years ago

How many different 7-place license plates are possible when 3 of the entries are letters and 4 are digits? Assume that repetitio

timofeeve [1]

Answer:

There are 6,151,600,000 different 7-place license plates are possible when 3 of the entries are letters and 4 are digits,

Step-by-step explanation:

For each of the entries which are letters, there are 26 possible outcomes.

For each of the entries which are digits, there are 10 possible outcomes.

These outcomes can be permutated.

For example, ABC1234 is a different outcome than A1B2C34. This means that we need to use the permutations formula.

The number of permutations of n, divided into two groups of size a and b, is:

$P_{a,b}^{n} = \frac{n!}{a!b!}$ .

In this problem, we have a permutation of 7, divided into a group of 4(digits) and 3(letters).

How many different 7-place license plates are possible when 3 of the entries are letters and 4 are digits?

This is $P_{3,4}^{7}*(26)^{3}*10^{4} = 35*(26)^{3}*10^{4} = 6,151,600,000$

There are 6,151,600,000 different 7-place license plates are possible when 3 of the entries are letters and 4 are digits,

7 0

3 years ago