A a fraction close to but greater than 1 1/2

Which of the following pairs are perpendicular? Select all that apply.

Blababa [14]

1st is parallel

2nd is perpendicular

3rd is perpendicular

4th is parallel

5th is perpendicular

6th is perpendicular

2nd, 3rd, 5th, and 6th

3 0

2 years ago

A scale model of the Vancouver Olympic cauldron is to be built in memory of the 2010 Olympics. If the scale to be used is 1:27,

timurjin [86]

Answer:

23/54 meters

Step-by-step explanation:

Assuming that the scale model is smaller, then the scale model should be 1/27th of the actual thing. Therefore:

11.5/27

= 23/54 meters tall

4 0

3 years ago

NEED HELP M<1 <br><br> Use the given information

kondor19780726 [428]

The line should equal 180 degrees, so we would subtract 122 from 180 to get 58 degrees. Since the triangle is equilateral, each angle is the same measure, so I believe m<1 should be 58 degrees.

7 0

2 years ago

Please answer asap it’s due in 1 min procrastination

Ipatiy [6.2K]

Answer:

r=ts/-qu

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

What is the answer to this solution. -7r−4≥ 4r+2

tia_tia [17]

Answer:

The solution is:

$-7r-4\ge \:\:4r+2\quad \::\quad \:\begin{bmatrix}\mathrm{Solution:}\:&\:r\le \:\:-\frac{6}{11}\:\\ \:\:\mathrm{Decimal:}&\:r\le \:\:-0.54545\dots \:\\ \:\:\mathrm{Interval\:Notation:}&\:(-\infty \:\:,\:-\frac{6}{11}]\end{bmatrix}$

Please check the attached line graph below.

Step-by-step explanation:

Given the expression

$-7r-4\ge \:4r+2$

Add 4 to both sides

$-7r-4+4\ge \:4r+2+4$

Simplify

$-7r\ge \:4r+6$

Subtract 4r from both sides

$-7r-4r\ge \:4r+6-4r$

Simplify

$-11r\ge \:6$

Multiply both sides by -1 (reverses the inequality)

$\left(-11r\right)\left(-1\right)\le \:6\left(-1\right)$

Simplify

$11r\le \:-6$

Divide both sides by 11

$\frac{11r}{11}\le \frac{-6}{11}$

Simplify

$r\le \:-\frac{6}{11}$

Therefore, the solution is:

$-7r-4\ge \:\:4r+2\quad \::\quad \:\begin{bmatrix}\mathrm{Solution:}\:&\:r\le \:\:-\frac{6}{11}\:\\ \:\:\mathrm{Decimal:}&\:r\le \:\:-0.54545\dots \:\\ \:\:\mathrm{Interval\:Notation:}&\:(-\infty \:\:,\:-\frac{6}{11}]\end{bmatrix}$

Please check the attached line graph below.

7 0

2 years ago