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maw [93]
3 years ago
12

Salisbury Middle School participated in a charity walk-a-thon. The data below shows the amount of money raised by the eighth gra

de classes. In a box-and-whisker plot for the data, which number would represent the third quartile?
{$140, $174, $148, $171, $150, $167, $152, $166}
A.
165
Mathematics
1 answer:
Ostrovityanka [42]3 years ago
7 0

Answer:

169 I believe

Step-by-step explanation:

Ifsifskfskfzfkxjf

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What is the value of the expression below?<br> -8 + 19 + 8<br> 0<br> 11<br> 19<br> 35
Inga [223]

Answer:

19

Step-by-step explanation:

-8+8=0

0+19=19

Hope it helps.

8 0
3 years ago
Allen has a photo that is 6 in by 8 in. What will the dimensions of the photo be if he scales it down by a factor of one-half ?
olchik [2.2K]
3 in by 4 in
because one half of 6 is three and one half of 8 is 4
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3 years ago
What is the multiplicative inverse of 1 over 2
SpyIntel [72]

Answer:

2

explanation;

it just is

6 0
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Read 2 more answers
In how many ways can 9 different pizza toppings be chosen from 23 available toppings?
kogti [31]

Answer:

296541907200

Step-by-step explanation:

23 * 22 * 21 * 20 * 19 * 18 * 17 * 16 * 15 = 296541907200

7 0
3 years ago
Simplify each expression. Assume that all variables are positive.
kozerog [31]
Q1. The answer is  \frac{8x^{3}y^{6}  }{27}

( \frac{16 x^{5} y^{10}}{81x y^{2} } )^{ \frac{3}{4} }= ( \frac{16}{81}* \frac{ x^{5} }{x}* \frac{ y^{10} }{y^{2}}   )^{ \frac{3}{4} } \\  \\ &#10;  \frac{ x^{a} }{ x^{b} }= x^{a-b}  \\  \\ &#10;( \frac{16}{81}* \frac{ x^{5} }{x}*\frac{ y^{10} }{y^{2}}   )^{ \frac{3}{4} }}=( \frac{16}{81 }* x^{5-1}* y^{10-2})^{ \frac{3}{4} }=( \frac{16}{81 }* x^{4}* y^{8})^{ \frac{3}{4} }= \\  \\ = (\frac{16}{18} )^{ \frac{3}{4} }*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} }=
\frac{(16)^{ \frac{3}{4} }}{(18)^{ \frac{3}{4} }}*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} }=\frac{( 2^{4} )^{ \frac{3}{4} }}{( 3^{4} )^{ \frac{3}{4} }}*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} } \\  \\ &#10; (x^{a} )^{b} = x^{a*b}  \\  \\ &#10;\frac{( 2^{4} )^{ \frac{3}{4} }}{( 3^{4} )^{ \frac{3}{4} }}*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} } =  \frac{ 2^{4* \frac{3}{4} } }{ 3^{4* \frac{3}{4} } } * x^{4* \frac{3}{4} } * y^{8*\frac{3}{4}} = \frac{ 2^{3} }{ 3^{3} } * x^{3} *y^{6} = 
= \frac{8x^{3}y^{6}  }{27}

Q2. The answer is 1/16

(-64) ^ \frac{-2}{3} =(-1* 2^{6} ) ^ \frac{-2}{3}=(-1)^ \frac{-2}{3} *(2^{6} ) ^ \frac{-2}{3} \\\\x^{-a} =  \frac{1}{ x^{a} } \\\\(-1)^ \frac{-2}{3} *(2^{6} ) ^ \frac{-2}{3} = \frac{1}{(-1)^ \frac{2}{3}} *\frac{1}{(2^{6})^ \frac{2}{3}} \\  \\  (x^{a} )^{b}=x^{a*b} \\\\x^{ \frac{a}{b} = \sqrt[b]{ x^{a} } }  \\  \\ &#10;
\frac{1}{(-1)^ \frac{2}{3}} *\frac{1}{2^{6*\frac{2}{3}}} = \frac{1}{ \sqrt[3]{(-1)^{2} } } * \frac{1}{ 2^{4} } =  \frac{1}{ \sqrt[3]{1} } * \frac{1}{16} = \frac{1}{1} * \frac{1}{16}= \frac{1}{16}


Q3. The answer is a^{ \frac{7}{6} }

a^{ \frac{2}{3} } * a^{ \frac{1}{2} }  \\  \\ &#10; x^{a}* x^{b}  =x^{a+b}  \\  \\ &#10;a^{ \frac{2}{3} } * a^{ \frac{1}{2} }= a^{ \frac{2}{3} + \frac{1}{2} } =a^{ \frac{2*2}{3*2} + \frac{1*3}{2*3} }=a^{ \frac{4}{6} + \frac{3}{6} }=a^{ \frac{4+3}{6} }=a^{ \frac{7}{6} }
7 0
3 years ago
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