Start with

Separate the variables:

Integrate both parts:

Which implies

Solving for y:

Since
is itself a constant, let's rename it
.
Fix the additive constant imposing the condition:

So, the solution is

4.25+1.25*m, 5.75+0.75*m
4.25+5.75=10 and 1.25+0.75 = 2 therefore the two expressions are 2m+10
0.5m-1.5 : 4.25+1.25+m-5.75+0.75*m =0.5m-1.5 ( I'm quite sure about this one but I can't think of another answer but this )
Answer: b, c and e.
Step-by-step explanation:
180° degree symmetry will mean that if we do a rotation of 180°, the figure will look exactly the same.
Now, let's suppose we have a figure with an odd number of sides.
We can draw that figure such that we have a side pointing down, and a vertex pointing up.
Now when we do a 180° rotation, the side will be pointing up and the vertex will be pointing down.
Then if the figure has an odd number of sides, it does not have a 180° rotational symmetry.
Now if the figure has an even number of sides, then we can do the same as above, but now we can put two parallel sides, one facing down and the other facing up, and when we do the rotation, we will end with the same image.
Then the correct options are the ones with an even number of sides:
b, c and e.
Answer:
22.5 miles per hour (rounded answer)
Step-by-step explanation:
This is a fraction equal to
18 miles ÷ 0.8 hours
We want a unit rate where
1 is in the denominator,
so we divide top and bottom by 0.8
18 miles ÷ 0.8
0.8 hours ÷ 0.8
=
22.5 miles
1 hour
=
22.5 miles
hour
= 22.5 miles per hour
Answer:1
1. 
2. ∠ABC = 120°, ∠BCD = 90°, ∠CDA = 60°, ∠DAB = 90°
Step-by-step explanation:
It's important to note here that the measure of all interior angles in a quadrilateral will add up to 360°
We know this using the formula
, a 4 sided figures angles will add up to

This means that all of the angles (4x, 3x, 2x, 3x) will add up to 360.

Combine like terms:

Divide both sides by 12:

We know now substitute x for 30 in for all of the side lengths.
∠ABC = 4x =
°
∠BCD = 3x =
°
∠CDA = 2x =
°
∠DAB = 3x =
°
Hope this helped!