Answer:
12 (p/2 + 17.50) = 750 equation can be used to get regular price of enrollment.
Step-by-step explanation:
So when a new student gets enrolled by paying a $17.50 application fee and gets a value of price halved at p/2
where p = regular price of enrollment
So in reality, for the student to be enrolled he/she must pay = (p/2) + $17.50 application fee to be able to get that special offer.
So Twelve new students enrolled, meaning they paid: 12 (p/2 + 17.50 application fee)
The amount they all paid is $750.
To get the regular price of enrollment from the price that included the application fees, the equation to use would be: 12 (p/2 + 17.50) = 750
100.014. I think this is it
PT=ST and QT=TR, when angles are verticals their opposite arcs are equivalent. i think. someone feel free to correct me if this is wrong
Part A:
From the figure shown.
The measure of line TH = 14' 72" = 14' + 72" / 12 = 14' + 6' = 20'
Given that the measure of line HI = 20'
Thus, triangle THI is an isosceles triangle with line TI as the base.
Part B:
To find the base angles we use the Pythagoras theorem.
Recall that the perpendicuar bisector of an isosceles triangle divides the triangle into two equal right triangles.
Dividing the base into two gives 22.5' / 2 = 11.25'
Thus, the perpendicular bisector divides the isosceles triangle into two equal right triangles with base of 11.25' and hypothenus of 20'.
By pythagoras theorem,

Therefore, the base angles is 55.77 degrees.
His original number was 8 because if you subtract 7-23=16 then 16/2=8