Answer:
4/15
Step-by-step explanation:
4/10*6/9
2/5*2/3
4/15
Points m and n
Are the answer
Answer:
a) weight of the car = 2816,1 lbs
b) 2773 lbs
Step-by-step explanation:
The equilibrium force is 490 lbs. That force keep the car at rest, then
∑ Fy = 0 and ∑Fx = 0
Forces acting on the car:
The external force 490 lbs
weight of the car uknown
Normal force
sin∠10° = 0,174
cos∠10° = 0.985
∑Fx = 0 mg*sin10°- 490 = 0 ∑Fy = 0 mg*cos10° - N = 0
mg*0,174= 490
mg = 490 / 0,174
mg = 2816,1 lbs
weight of the car = 2816,1 lbs
The Normal force
mg*cos10° - N = 0 2816,1 * 0,985 = N
N = 2773 lbs
Then equal force in magnitude and in opposite direction will car exets on the driveway
Original Price = Final Price / (100 - Discount)
So...
OP = 360 / 100 - 0.40
OP = 360 / 0.60
OP = 600
The original price is $600.
To check, do 600 - (600 * 0.40) in a calculator. You get 600 - 240 = 360, the discounted cost.
