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Igoryamba
4 years ago
14

3. Given 4x − 8y = 8: (a) Transform the equation into slope-intercept form. (b) Find the slope and y-intercept of the line. (c)

Find the equation, in point-slope form, of the line that is perpendicular to this line and passes through the point .
Mathematics
1 answer:
finlep [7]4 years ago
6 0
4x - 8y = 8
4x - 8 = 8y
y = 1/2x - 1 slope = 1/2 y intercept = -1

Perpendicular slope is negative reciprocal so 1/2 becomes -2

Perpendicular line formula is y = -2x - 1
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Write words to match the equation. b + 5 = 12
TiliK225 [7]

Answer:

a number plus 5 equals 12.

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Solve.
Artist 52 [7]

Answer:

(5,-3) if the system is

y=x-8

2x+3y=1

Step-by-step explanation:

I think the system is to read:

y=x-8

2x+3y=1.

Please correct me if I'm wrong.

I'm going to plug 1st equation into 2nd equation giving me:

2x+3(x-8)=1      ->I replaced y with (x-8).

Distribute:

2x+3x-24=1

Combine like terms:

5x-24=1

Add 24 on both sides:

5x=25

Divide both sides by 5:

x=5

If y=x-8 and x=5, then y=5-8=-3.

The solution is (5,-3).

7 0
3 years ago
Assume that θ is an acute angle in a right triangle satisfying the given conditions. Evaluate the 5 remaining trigonometric func
neonofarm [45]

Answer: See step by step. Replace the x with theta

Step-by-step explanation: Since sin is less than zero, and secant is positive. This means the trig values are in Quadrant 4.

We know that secФ=17/15. We need to find sin,cos,tan,csc, and cot.

We can find tangent by using the identity

tan^{2} (x)+ 1=sec^{2} (x) where x is theta.

tan^{2} (x)+1=\frac{289}{225}

tan^{2} (x)+\frac{225}{225} =\frac{289}{225}

tan^{2}(x)=\frac{64}{225}

tan x=\frac{8}{15}, Tangent in the fourth  quadrant is negative  so  the answer is instead

tan x= -\frac{8}{15}

We can find cotangent by taking the recipocial of tan so

cot=-\frac{15}{8}

We can find cos by taking reciprocal of sec remeber that cosine is positive in 4th quadrant so the answer is

cos =\frac{15}{17}

We can find sin by doing quoteint identies.

\frac{sin x}{cos x} =tan x

\frac{ sin x}{15/17} =-\frac{8}{15}

sin x= -\frac{8}{17}

To find csc, take reciprocal of sine.

csc=\frac{-17}{8}

7 0
3 years ago
The graph shows the distance in miles of a runner over x hours. What is the average rate of speed over the interval [9, 11]?
ELEN [110]

Question:

The graph shows the distance in miles of a runner over x hours. What is the average rate of speed over the interval [9, 11]?

A. 2/5

B. 1

C.2

D.5/2

The image of the graph is attached below.

Answer:

Option D: 5/2 is the average speed over the interval [9,11]

Explanation:

The graph shows the distance in miles of a runner over x hours.

Now, we need to determine the average rate of speed over the interval [9,11]

The x-axis represents the time taken.

The y-axis represents the distance.

To find the average speed, let us use the formula for speed which is given by

speed=\frac{distance}{time}

Thus, substituting the coordinates (9,6) and (11,11), we have,

speed=\frac{11-6}{11-9} =\frac{5}{2}

Hence, the average speed over the interval [9,11] is \frac{5}{2}

8 0
3 years ago
Read 2 more answers
The speed that a tsunami can travel is modeled by the equation , where s is the speed in kilometers per hour and d is the averag
dusya [7]

The approximate depth of water for a tsunami traveling at 200 kilometers per hour, given the equation S=356√d, where S is the speed in kilometers per hour and d is the average depth of the water in kilometers, is <u>0.32 km</u>. Hence, <u>option A</u> is the correct choice.

To solve for the average depth of water, when the water is traveling at 200 kilometers per hour, we substitute speed S = 200, in the relation S = 356√d.

This will be solved in the following way:

S = 356√d,

or, 200 = 356√d {Substituting S = 200},

or, 200/356 = (356√d)/356 {Dividing both sides by 356},

or, √d = 0.5618 {Simplifying},

or, d = 0.32 kilometers.

Therefore, the approximate depth of water for a tsunami traveling at 200 kilometers per hour, given the equation S=356√d, where S is the speed in kilometers per hour and d is the average depth of the water in kilometers, is <u>0.32 km</u>. Hence, <u>option A</u> is the correct choice.

The provided question is incomplete.

The complete question is:

"The speed that a tsunami can travel is modeled by the equation S=356√d, where S is the speed in kilometers per hour and d is the average depth of the water in kilometers. What is the approximate depth of water for a tsunami traveling at 200 kilometers per hour?

A. 0.32 km

B. 0.75 km

C. 1.12 km

D. 3.17 km"

Learn more about speed and depth relation at

brainly.com/question/2456082

#SPJ4

5 0
2 years ago
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