Question

67a(t+z)=45z+67 solve for z. I need help. Please?

Answer 1

Hello there, let's get started.

The equation is 67a(t+z)=45z+67.

Let's first distribute "67a" to the "t" and "z" in the parenthesis.
The equation simplifies to: 67at + 67az = 45z + 67. 

Step one is to Add -45z to both sides. 67at+67az+−45z=45z+67+−45z (this crosses 45z out), it is now simplified to 67at+67az−45z=67. 

Step 2 is to now add -67at to both sides. 67at+67az−45z+−67at (this crosses 67at out)=67+−67a. The equation is now simplified to 67az−45z=−67at+67t. 

Step 3: Factor out variable z. z(67a−45)=−67at+67. 

Step 4: Divide both sides by 67a-45. z(67a−45)/67a−45=−67at+67/67a−45.
It's then simplified to: z=−67at+67/67a−45.

The equation: z=−67at+67/67a−45 is the final answer. Sorry if this is confusing.

Answer 2

67a(t+z)=45z+67
Distribute the 67a to inside the parenthesis.
67at + 67az = 45z + 67
Subtract 67 to the other side.
67at + 67az - 67 = 45z
Divide everything by 45.
1.49at + 1.49az - 1.49 = z

Hope that helped! :)