67a(t+z)=45z+67 solve for z.
I need help. Please?
2 answers:
Hello there, let's get started. <span> The equation is 67a(t+z)=45z+67. Let's first distribute "67a" to the "t" and "z" in the parenthesis. The equation simplifies to: 67at + 67az = 45z + 67. Step one is to </span>Add -45z to both sides. 67at+67az+− 45z =45z+67+− 45z (this crosses 45z out), it is now simplified to 67at+67az−45z=67. Step 2 is to now add -67at to both sides. 67at+67az−45z+− 67a t (this crosses 67at out) =67+− 67a. The equation is now simplified to 67az−45z=−67at+67 t . Step 3: Factor out variable z. z(67a−45)=−67at+67. Step 4: Divide both sides by 67a-45. z(67a−45)/67a −45 =−67at+67/67a −45. It's then simplified to: z= − 67a t +67/ 67a −45. The equation: z= − 67a t +67/ 67a −45 is the final answer. Sorry if this is confusing.
67a(t+z)=45z+67 Distribute the 67a to inside the parenthesis. 67at + 67az = 45z + 67 Subtract 67 to the other side. 67at + 67az - 67 = 45z Divide everything by 45. 1.49at + 1.49az - 1.49 = z Hope that helped! :)
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