Answer:

149 engines in 9th year
Step-by-step explanation:
I think your question is missed of key information, allow me to add in and hope it will fit the original one.
Please have a look at the attached photo.
My answer:
From a look at the photo and the data plot can be represented by the function, so we can pick 2 points in our given graph
- (x1, y1) = (2,60)
- (x2, y2) = (5,99)
The standard form of a linear equation is:
y = mx + b where:
- m is the slope
- b is the y-intercept
We know the slope of the function can be found as following:
so in this situation we have:
<=> 
=> y = 13x + b (1)
Because the line goes through point (2,60) so we substitute it into (1):
60 = 13*2 + b
<=> b = 60 - 26 = 34
=> y = 13x + 34
Now we will substitute x=9 to find the engines produced by company in 9th year as:

Hence, the company will produce 149 engines in 9th year
Answer:
x =8.34654305
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
cos theta = adjacent / hypotenuse
cos 33 = 7/x
Switching places with the x and the 33
x = 7/ cos 33
x =8.34654305
Answer:
![\large\boxed{\ln\sqrt[3]{e^4}=\dfrac{4}{3}}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7B%5Cln%5Csqrt%5B3%5D%7Be%5E4%7D%3D%5Cdfrac%7B4%7D%7B3%7D%7D)
Step-by-step explanation:
![\text{Use}\\\\\sqrt[n]{a^m}=a^\frac{m}{n}\\\\\ln a^n=n\ln a\\\\\ln e=1\\-----------\\\\\ln\sqrt[3]{e^4}=\ln e^\frac{4}{3}=\dfrac{4}{3}\ln e=\dfrac{4}{3}\cdot1=\dfrac{4}{3}](https://tex.z-dn.net/?f=%5Ctext%7BUse%7D%5C%5C%5C%5C%5Csqrt%5Bn%5D%7Ba%5Em%7D%3Da%5E%5Cfrac%7Bm%7D%7Bn%7D%5C%5C%5C%5C%5Cln%20a%5En%3Dn%5Cln%20a%5C%5C%5C%5C%5Cln%20e%3D1%5C%5C-----------%5C%5C%5C%5C%5Cln%5Csqrt%5B3%5D%7Be%5E4%7D%3D%5Cln%20e%5E%5Cfrac%7B4%7D%7B3%7D%3D%5Cdfrac%7B4%7D%7B3%7D%5Cln%20e%3D%5Cdfrac%7B4%7D%7B3%7D%5Ccdot1%3D%5Cdfrac%7B4%7D%7B3%7D)
Answer:
This equation has 2 solutions.
1. 
2. 