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Savatey [412]
3 years ago
7

Given a point on a line and the equation of a parallel or perpendicular line, write the equation of the line in point-slope form

.
Pt on the line : (1,5)
Parallel to y=7
Mathematics
1 answer:
Arlecino [84]3 years ago
6 0

Answer: y - 5 = 0(x - 1)

==================================================

Explanation:

Recall that point slope form in general is written as such

y - y1 = m(x - x1)

where,

m is the slope

(x1,y1) is the point the line goes through

The given equation y = 7 can be written as y = 0x+7. So we see that this line has a slope of m = 0

Plug m = 0 along with the given point (x1,y1) = (1,5) into the point slope equation and we get

y - y1 = m(x - x1)

y - 5 = 0(x - 1)

which is the final answer

note: the equation in bold can be rearranged and simplified to get y = 5; however your teacher seems to want the answer in point-slope form, so we leave it as such.

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Suppose after 2500 years an initial amount of 1000 grams of a radioactive substance has decayed to 75 grams. What is the half-li
krok68 [10]

Answer:

The correct answer is:

Between 600 and 700 years (B)

Step-by-step explanation:

At a constant decay rate, the half-life of a radioactive substance is the time taken for the substance to decay to half of its original mass. The formula for radioactive exponential decay is given by:

A(t) = A_0 e^{(kt)}\\where:\\A(t) = Amount\ left\ at\ time\ (t) = 75\ grams\\A_0 = initial\ amount = 1000\ grams\\k = decay\ constant\\t = time\ of\ decay = 2500\ years

First, let us calculate the decay constant (k)

75 = 1000 e^{(k2500)}\\dividing\ both\ sides\ by\ 1000\\0.075 = e^{(2500k)}\\taking\ natural\ logarithm\ of\ both\ sides\\In 0.075 = In (e^{2500k})\\In 0.075 = 2500k\\k = \frac{In0.075}{2500}\\ k = \frac{-2.5903}{2500} \\k = - 0.001036

Next, let us calculate the half-life as follows:

\frac{1}{2} A_0 = A_0 e^{(-0.001036t)}\\Dividing\ both\ sides\ by\ A_0\\ \frac{1}{2} = e^{-0.001036t}\\taking\ natural\ logarithm\ of\ both\ sides\\In(0.5) = In (e^{-0.001036t})\\-0.6931 = -0.001036t\\t = \frac{-0.6931}{-0.001036} \\t = 669.02 years\\\therefore t\frac{1}{2}  \approx 669\ years

Therefore the half-life is between 600 and 700 years

5 0
3 years ago
CAN SOMEONE PLEASE ANSWER 11,13,14,15 ?
blondinia [14]

Answer:

<h3><em>I gotchu</em></h3><h3><em /></h3><h3><em>These are all fractions btw. </em></h3>

<em />

11.   -9/32

12. -3/5

13. 4/7

14. 3/8

15. 3/4

Step-by-step explanation: When you do these problems, it's fairly simple. just make sure you plug the numbers in the correct spots. having a calculator help a lot too!

4 0
3 years ago
Is the square root of 225 a rational number?
MArishka [77]

Step-by-step explanation:

\text{The principal square root}:\\\\\sqrt{a}=b\iff a^2=b\ \text{for}\ a\geq0\ \text{and}\ b\geq0.\\\\\text{The square root:}\\\\\sqrt{a}=b\iff b^2=a\ \text{for}\ a\geq0\\===================

\text{If you want the principal square root (arithmetic square root):}\\\\\sqrt{225}=15\ \text{because}\ 15^2=225\\\\\text{If you want square root (algebraic square root):}\\\\\sqrt{225}=\pm15\ \text{because}\ (-15)^2=225\ \text{and}\ 15^2=225

7 0
3 years ago
Read 2 more answers
A donation center had filled up 44 small bins with canned food with each bin containing 24 cans. They plan to send the cans out
Valentin [98]
Each food bank would receive 264 cans.



44 Bins with 24 cans. 44•24= 1,056

n= (44•24) / 4
n= 1,056 / 4
n= 264 cans per food bank
8 0
3 years ago
The table shows the results of an experiment in which subjects taking either a drug or a placebo either reported fatigue or did
Lady bird [3.3K]

Answer:

Therefore, the correct options are;

-P(fatigue) = 0.44

P(fatigue \left |  \right drug) = 0.533

--P(drug and fatigue) = 0.32

P(drug)·P(fatigue) = 0.264

Step-by-step explanation:

Here we have that for dependent events,

P(A \, and \, B)= P(A)\times  P(B\left |  \right A )

From the options, we have;

P(fatigue \left |  \right drug) = 0.533

P(drug) = 0.6

P(drug and fatigue) = 0.32

Therefore

P(drug and fatigue) = P(drug)×P(fatigue \left |  \right drug)  

= 0.6 × 0.533 = 0.3198 ≈ 0.32 = P(drug and fatigue)

Therefore, the correct options are;

-P(fatigue) = 0.44

P(fatigue \left |  \right drug) = 0.533

--P(drug and fatigue) = 0.32

P(drug)·P(fatigue) = 0.264

Since P(fatigue) = 0.44 ∴ P(drug) = 0.264/0.44 = 0.6.

4 0
3 years ago
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